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lozanna [386]
3 years ago
9

Solve for c. 55c+13 < 750 +39

Mathematics
2 answers:
kaheart [24]3 years ago
6 0

Answer:

C is greater than or equal to -13/10

Step-by-step explanation:

iren [92.7K]3 years ago
5 0

Answer:

c = anything less than 14.1

Step-by-step explanation:

55c+13 < 750 + 39

55c+13 < 789

55c < 776

c < 14.1

Hope It Helps

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Solve the following differential equation: y" + y' = 8x^2
PtichkaEL [24]

Answer:

y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}

Step-by-step explanation:

Let's  find a particular solution. We need a function of the form y= ax^3+bx^2+cx+d such that

y'= 3ax^2+2bx+c and

y''= 6ax+2b

y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a =  8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is  y_p= \frac{8}{3}x^3-8x^2+16x.

Now, let's find the solution y_p of the homogeneus equation y''+y'=0 with the method of constants coefficients. Let y=e^{\lambda x}

y'=\lambda e^{\lambda x}

y''=\lambda^2e^{\lambda x}

then \lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0

e^{\lambda x}(\lambda +\lambda^2)= 0

(\lambda +\lambda^2)= 0

\lambda (1+\lambda)= 0

\lambda =0 and \lambda)= -1.

So, y_h = C_1 + C_2e^{-x} and the solution is

y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}.

5 0
3 years ago
9x+1/2y51<br> 7x+1/3y=39
olga2289 [7]
What’s the question though lol
7 0
3 years ago
What is the volume of the right triangular prism?( please input your answer as a number without a unit.)
77julia77 [94]

I hope this helps you

V=Base Area×Height

V=4.8/2×12

V=16×12

V=196

4 0
3 years ago
A class is made up of 8 boys and 4 girls. Half of the girls wear glasses. A student is selected at random from the class. What i
Ierofanga [76]

Answer:

1/6

Step-by-step explanation:

The total amount of people 8+4=12

there are 4/2=2 girls with glasses

the probability to chhose a girl with glasses is 2/12=1/6

3 0
2 years ago
An objects weight on Mars is 38% of its weight on Earth. If an object weighs p, pounds on Earth, write an expression for its wei
oksano4ka [1.4K]

0.38p

To get the percent of something, you turn the percent to a decimal and multiply it to the number.

Here, we want the expression to get 38% of p. So we turn 38% to 0.38 and multiply it to p. Since we don't know what p is, we have to leave it as 0.38p

The answer is 0.38p


Hope this helps!

3 0
3 years ago
Read 2 more answers
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