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never [62]
3 years ago
10

Please help!?! Last grade for my 4th quarter of quarantine school!

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:3x^2-5x=-8 is the one that has 2 complex solutions

Step-by-step explanation:

xenn [34]3 years ago
4 0
All except the 12x=9x2+4
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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
Zack bought a coat for $69.78. He paid with $100 bill and received $26.73 in change. How much was the sales tax?
Klio2033 [76]
$3.49

Hopefully I helped!
6 0
3 years ago
Read 2 more answers
Help me with this!!!!
andrezito [222]

Answer: I think it would be 3.5

Step by Step Explanation: BRAINLIEST?!?

8 0
3 years ago
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I need help please :(
zloy xaker [14]

Answer:

-(1/3 · 1/3 · 1/3 · 1/3 )

Step-by-step explanation:

-(3)^-4= -1/3 ^4 = -1/81

-(1/3 · 1/3 · 1/3 · 1/3 )= -1/81

7 0
3 years ago
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Which of the following statements is logically equivalent to "If I study, then I get better grades"? If I do not study, then I d
saul85 [17]
It would go along with, "if I get better grades, then I study."
3 0
3 years ago
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