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2 years ago

Plz help- solve the inequality -3(1 - z) < 9 Use distributive property

Mathematics

1 answer:

Aleksandr [31]2 years ago

5 0

Answer:

Step-by-step explanation:

anyway

good luck

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Answer:

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Step-by-step explanation:

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3 years ago

How can we predict the sign of the product or quotient of sign numbers?

Andru [333]

Two positives make a positive
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2 years ago

two men working together can complete a job in 1 hour 20 minutes. the first man working alone can complete the task in two hours

lana [24]

Answer:

Second Man = (2 Hours * 1.3333 Hours) / (2 Hours - 1.3333 Hours)

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Step-by-step explanation:

6 0

3 years ago

Which equation has the same solution as w / 3.9 = 3? A. w+0.6=1.9 B. w-0.6 = 11.1 C. w+1.03=2.93 D. w-1.03=8.24

cestrela7 [59]

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

<em>Check all that applies</em>

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Learn more about equation:

brainly.com/question/2972832

6 0

2 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

5 0

3 years ago