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SVETLANKA909090 [29]
3 years ago
14

En una clase de 25 alumnos hay 15 cajas de lápices de colores. Cada caja contiene 20 lápices. Queremos que todos los alumnos ten

gan el mismo número de lápices. ¿Cuántos lápices tendrá cada alumno?
Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer: Each student will have 12 pencils.

Step-by-step explanation:

Given:  Total students= 25

Total colored boxes = 15

Total pencils in 1 box =20

Then total pencils in all 15 boxes = 20 × 15 = 300

Now, the number of pencils each students will get = (Number of pencils in all 15 boxes) ÷ (Total students)

= 300÷ 25

= 12

Therefore, Each student will have 12 pencils.

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18,20/4.5,5 what is the slope
Lyrx [107]

Answer:

10/9 or 1.1 repeating

Step-by-step explanation:

Use formula y2-y1/x2-x1.

If you liked my answer please make it the brainliest that would be much appreciated. Thanks!

7 0
3 years ago
Show all steps please
OLga [1]
9-8x\geq0\ \ \ |subtract\ 9\ from\ both\ sides\\\\-8x\geq-9\ \ \ \ |change\ signs\\\\8x\leq9\ \ \ \ |divide\ both\ sides\ by\ 8\\\\x\leq9\\\\  |9-8x|=\left\{\begin{array}{ccc}9-8x&for\ x\leq9\\8x-9&for\ x \ \textgreater \  9\end{array}\right

1^o\ x\in(-\infty;\ 9]\to|9-8x|=9-8x\\\\9(9-8x)=2x+3\\81-72x=2x+3\ \ \ \ |subtract\ 81\ from\ both\ sides\\-72x=2x-78\ \ \ \ |subtract\ 2x\ from\ both\ sides\\-74x=-78\ \ \ \ |divide\ both\ sides\ by\ (-74)\\\\x=\dfrac{-78:2}{-74:2}\\\\\boxed{x=\frac{39}{37}}\in(-\infty;\ 9]

2^o\ x\in(9;\ \infty)\to|9-8x|=8x-9\\\\9(8x-9)=2x+3\\72x-81=2x+3\ \ \ \ |add\ 81\ to\ both\ sides\\72x=2x+84\ \ \ \ |subtract\ 2x\ from\ both\ sides\\70x=84\ \ \ \ \ \ |divide\ both\ sides\ by\ 70\\\\x=\dfrac{84:14}{70:14}\\\\x=\dfrac{6}{5}\notin(9;\ \infty)\\\\\\Answer:\boxed{x=\frac{39}{37}}
6 0
3 years ago
If csc theta = 8/7, which equation represents (cot theta) ?
Paul [167]

Out of the given choice, the equation represents \cot \theta=\frac{\sqrt{15}}{7}.

Answer: Option B

<u>Step-by-step explanation:</u>

We know, \csc \theta=\frac{1}{\sin \theta}

                \sin \theta=\frac{1}{\csc \theta}

Given data:

                \csc \theta=\frac{8}{7}

So, now sin theta can express as

                \sin \theta=\frac{7(\text { opposite })}{8(\text { Hypotenuse })}

Sin theta defined by the ratio of opposite to the hypotenuse. In general, the adjacent can be calculated by,

           \text {(opposite) }^{2}+(\text { adjacent })^{2}=(\text {Hypotenuse})^{2}

          7^{2}+(\text { adjacent })^{2}=8^{2}

         (\text {adjacent})^{2}=8^{2}-7^{2}=64-49=15

Taking square root, we get

           \text { adjacent }=\sqrt{15}

Also, we know the formula for cot theta,

         \cot \theta=\frac{1}{\tan \theta}=\frac{1}{\left(\frac{\sin \theta}{\cos \theta}\right)}=\frac{\cos \theta}{\sin \theta}

Cos theta denoted as the ratio of adjacent to the hypotenuse.

           \cos \theta=\frac{\sqrt{15}(\text {Adjacent})}{8(\text {Hypotenuse})}

Therefore, find now as below,

           \cot \theta=\frac{\left(\frac{\sqrt{15}}{8}\right)}{\left(\frac{7}{8}\right)}=\frac{\sqrt{15}}{8} \times \frac{8}{7}=\frac{\sqrt{15}}{7}

7 0
3 years ago
Read 2 more answers
Hello! :)<br> Please help me. Thanks! <br> ~ Destiny ^_^
andrey2020 [161]

Answer:

720 in³

Step-by-step explanation:

The volume (V) of a right prism is calculated as

V = area of triangular end × length

area of Δ = \frac{1}{2} bh

where b is the base and h the perpendicular height

here b = 8 and h = 15, thus

area of Δ = 0.5 × 8 × 15 = 4 × 15 = 60 in²

The length of the prism is 12 in, hence

V = 60 × 12 = 720 in³

6 0
3 years ago
In circle M with m \angle LMN= 46m∠LMN=46 and LM=7LM=7 units, find the length of arc LN. Round to the nearest hundredth.
Rus_ich [418]

Answer:

l =  5.62 units

Step-by-step explanation:

The formula for measuring the length of an arc is expressed as;

l = r \theta

r is the radius

\theta is the central angle in radians

r = LM = 7units

\theta = \frac{46 \pi}{180} \\\theta = \frac{23 \pi}{90} \\

Substitute into the formula

l = 7 \times \frac{23 \pi}{90}  \\l = 7 \times \frac{23 \times 3.14}{90}  \\l = 7 \times 0.8024\\l =  5.62 units

Hence the length of arc LN is 5.62 units to the nearest hundredth

4 0
2 years ago
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