<h3>Answer:</h3><h3>Exact volume =
32pi</h3><h3>Approximate volume =
100.48</h3>
The approximate volume only applies when pi = 3.14
Use either answer, but not both of course.
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Work Shown:
V = volume of cylinder
V = pi*r^2*h
V = pi*2^2*8
V = pi*32
V = 32pi .... exact volume in terms of pi
V = 32*3.14
V = 100.48 .... approximate volume when we use pi = 3.14
Answer:
(69)(3)−8
=
15
199≠15
False
Step-by-step explanation:
hope it helps, 69(3) is already bigger than 15, then -8 makes it 199, which is definitely not equal to 15.
Answer:
-500
Step-by-step explanation:
Train A is moving at a faster rate because the line is steeper.
Hope this helps :)
Step-by-step explanation:
P varies directly as the cubic root of Q means that:
![p = x \times \sqrt[3]{q}](https://tex.z-dn.net/?f=p%20%3D%20x%20%5Ctimes%20%20%5Csqrt%5B3%5D%7Bq%7D%20)
, where x is a real constant number.
Which means that:
![x = \frac{p}{ \sqrt[3]{q} }](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7Bp%7D%7B%20%5Csqrt%5B3%5D%7Bq%7D%20%7D%20)
for q ≠0.
So we get that for q=8,p=4 which means:
![x = \frac{4}{ \sqrt[3]{8} } = \frac{4}{2} = 2](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B4%7D%7B%20%5Csqrt%5B3%5D%7B8%7D%20%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B2%7D%20%20%3D%202)
As a result we get that for Q=64:
![p = 2 \times \sqrt[3]{64} = 2 \times 4 = 8 \\ since \: {4}^{3} = 4 \times 4 \times 4 = \\ 16 \times 4 = 64](https://tex.z-dn.net/?f=p%20%3D%202%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B64%7D%20%20%3D%202%20%5Ctimes%204%20%3D%208%20%5C%5C%20since%20%5C%3A%20%20%7B4%7D%5E%7B3%7D%20%20%3D%204%20%5Ctimes%204%20%5Ctimes%204%20%20%3D%20%20%5C%5C%20%2016%20%5Ctimes%204%20%3D%2064)
So for q=64,p=8.
