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3 years ago

Z+w−3=k 6z−10w=8

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

6 0

Answer:

if your looking for z it is 5/8k+2.375

Step-by-step explanation:

madam [21]3 years ago

5 0

Answer:

Step-by-step explanation:

Please, include the instructions.

I'm assuming you want to solve this system of linear equations for z and w, assuming that k is an unknown constant.

Use the method of elimination by addition and subtraction. To eiiminate w, multiply all four terms of the first equation by 10, obtaining:

10 z + 10w - 30 = 10k

6z - 10 w = 80

Then 16z - 30 - 80 = 10k, or

16z -110 = 10k, Simplifying this, we get:

10(k + 11)

z = ---------------

Substituting this expression for z into the first equation, we get:

(10/16)(k + 11) + w - 3 = k. We must solve this for w:

-(10/16)(k + 11) + w - 3 = k), or

-(10/16)(k + 11) - w + 3 = -k

Then -(10/16)(k + 11) + 3 + k = w

and so the solution, in terms of the unknown constant k, is

10(k + 11)

( --------------, -(10/16)(k + 11) + 3 + k )

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<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

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3 years ago

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Ivan

Answer: $\pm0.1706$

Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of $\alpha:0.05$ : $z_{\alpha/2}= 1.96$

Sample mean : $\overline{x}=2.5$

Standard deviation : $\sigma= 0.5$

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Step-by-step explanation:

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3 years ago

Z+w−3=k 6z−10w=8 ​ ​

Z+w−3=k 6z−10w=8