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weeeeeb [17]
3 years ago
7

Classwork for Ms. O'Brien's (Root X

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0

Answer:

4673 mm²

Step-by-step explanation:

<u>Data</u>

  • base: 51.7 mm
  • height: 90.39 mm

iPhone's screen is a rectangle. The area of rectangle is calculated as base*height. Replacing with data we get:

Area of rectangle = area of the iPhone's screen = 51.7 mm * 90.39 mm =  4673.163 mm² ≈ 4673 mm²

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Assume that you counted all the CFL bulbs in your house.
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Answer:

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Step-by-step explanation:

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3 years ago
A.perform the indicated operation.<br><br> 1.(6x-4)+(-2x+2)<br> Solution and answer:
Anestetic [448]

Answer:

4x - 2

Step-by-step explanation:

(2(3x-2))+(-2(x-1))

2(3x-2)-2(x-1)

2(3x-2-(x-1))

2(3x-2-<u>x</u><u>+</u><u>1</u><u>)</u>

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3 0
4 years ago
What is the area of this<br>irregular shape?<br>.6 ft<br>square feet<br>3 ft<br>8 ft<br>16 ft<br>​
Andrej [43]

Answer:

Step-by-step explanation:

area=16×8+1/2×3×6

=128+9

=137 sq. ft.

5 0
3 years ago
As x → − ∞ , f ( x ) = − 3 . As x → ∞ , f ( x ) = − 3
Ludmilka [50]

Answer:

hi

Step-by-step explanation:

4 0
2 years ago
A machine at Katz Steel Corporation makes 5-inch-long nails. The probability distribution of the lengths of these nails is appro
Lilit [14]

Answer:

The answer for this case would be 0.0027.

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the lengths the nails produced by a machine at Katz Steel Corporation. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =5,\sigma =0.12)

The quality control inspector takes a sample of n=36 nails. That represent the sample size.

And we want to calculate the probability that the mean of this sample is either less than 4.94 inches or greater than 5.06 inches. So we want to find:

P(\bar X 5.06)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the individual probabilities like this:

P(\bar X

And using a calculator, excel ir the normal standard table we have that:

P(Z

And for the other individual probability we have:

P(\bar X >5.06)=P(Z>\frac{5.06-5}{\frac{0.12}{\sqrt{36}}}=3)

P(Z>3)=1-P(Z

And then we can find the probability required on this way:

P(\bar X 5.06)=P(\bar X 5.06)-[P(\bar X5.06)]

=P(\bar X 5.06)-0= 0.00135+0.00135=0.0027

What is the probability that based on a sample of 36 nails, the inspector will conclude that the machine needs an adjustment?

The answer for this case would be 0.0027.

8 0
4 years ago
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