Answer:
The answer to your question is 0.34 M
Explanation:
Data
[Sr(OH)₂] = ?
Volume of Sr(OH)₂ = 35.6 ml or 0.0356 l
[HBr] = 0.0445 M
Volume of HBr = 0.549 l
Balanced chemical reaction
2HBr + Sr(OH)₂ ⇒ SrBr₂ + 2H₂O
Process
1.- Calculate the moles of HBr
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.0445 x 0.549
= 0.0244
2.- Calculate the moles of Sr(OH)₂ using the coefficients of the balanced reaction
2 moles of HBr ----------------------- 1 mol of Sr(OH)₂
0.0244 moles ----------------------- x
x = (0.0244 x 1) / 2
x = 0.0122 moles of Sr(OH)₂
3.- Calculate the concentration of Sr(OH)₂
Molarity = 0.0122/ 0.0356
-Simplification
Molarity = 0.34
PV=nRT
You are funding pressure and you have V = 9.45L, n = 1.9 moles, R = gas constant, and T = 228 K
P(9.45L) = (1.9moles)(0.0821)(228K)
Find P
Multiply
9.45P = 35.57
Divide
P = 3.76 L of N
Answer should be 3.76 liters of nitrogen
Answer:
Explanation:
Here, a balance between attraction between nucleus and electrons, and electron-electron, and nuclei-nuclei repulsion play role.
All chemical bonds are formed by overlapping of orbitals. If the electronegativity of the two elements forming the bond is very different (elements from the 1st ,2nd groups with elements of 7th group) then ionic bond are formed. If the electronegativities are more similar, then overlapping is stronger, and covalent bonds are formed.
Answer:
the region of negative charge surrounding an atomic nucleus that is associated with an atomic orbital. The region is defined mathematically, describing a region with a high probability of containing electrons.
Explanation:
