In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
The sum of the number of protons and neutrons in the nucleus of an atom is called the mass number (A), or nucleon number.
Hey there!
Molar mass :
<span>
BaCrO</span>4 = 253.319 g/mol
(g/L) = molar solubility * molar mass
(g/L) = ( 1.10 x 10⁻⁵ ) * 253.319
=> 2.79x10⁻³ g/L
Explanation:
It is given that volume of 
is 300 mL and molarity is 0.200 M.
Volume of NaCl is 200 mL and molarity is 0.050 M.
The chemical reaction will be as follows.
for 
is given as 
.
As, molarity is number of moles present in liter of solution.
Hence, moles of 
(aq) will be calculated as follows.
moles of (aq) = 
= 0.06 mol
![[Pb^{2+}]](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D)
= 
= 0.120 M
Mole of 
= 
= 0.010 M
Now, Q = ![[Pb^{2+}][Cl^{-}]^{2}](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D)
= 
= 
As, Q < hence, there will be no formation of precipitate.
I am not sure bout this question sry
