What times what = 36 like two of the same numbers. then multiply that number by 4 for the number of sides and u get the perimiter. (sry if confusing so ill explain that 6×6=36)
Answer:
27.2 cm
Step-by-step explanation:
14 cm / 2.5 = 5.6 cm, and
20 cm / 2.5 = 8 cm.
Then the new perimeter would be P = 2L + 2W, or, in this case:
P = 2(8 cm) + 2(5.6 cm) = 27.2 cm
Answer:
7.31 x 10^-23
<em>Answer: CO2 (1 atom of carbon and 2 atoms of oxygen)</em>
3.34 x 10^-24
<em>Answer: H2 (2 atoms of hydrogen)</em>
2.821 x 10^-23
<em>Answer: NH3 (1 atom of nitrogen and 3 atoms of hydrogen)</em>
7.64 x 10^-23
<em>Answer: NO2 (1 atom of nitrogen and 2 atoms of oxygen)</em>
Step-by-step explanation:
hope this helps :)
After I looked up some quick information, your car loses 15-25% each year. After 5 years, it goes to only 37%. So, a car that would cost 20000 would be valued at around 7k after 5 years. So, in the first 5 years, it lost 14k. Also, a 1999 Corolla goes for 2.5k, and that's nearly 20 years. So, I'm just going to go with, based off these numbers, probably 25-30 years...if it still works by then.
Also, if you get in a heavy accident the next day, making the car unusable, you rip off your friend. The first scenario only applies if the engine works well and no accidents were on the vehicle either.
Answer:
A=10,000(1+.02/12)^4*t
Step-by-step explanation:
First off u need to know how many years to get the answer but for the rest:
P- is principle and is the amount you are starting with, in this case 10,000.
You can either use 1+ or 1- this depends on wheather the amount is increasing or decreasing
Increasing: 1+ ; Decreasing: 1
(The problem already has it for you)
R- is the rate, here you take the percentage and move the decimal twice to the left. In this problem 2% moved to the left is .02.
N- Depends on what the problems says
Quarterly- 4 (cuz it means 4)
Daily- 365 (Number of days in a year)
Weekly- 52 (Number of weeks in a year)
Monthly- 12 (Number of months in a year)
Yearly- 1 ( One year)
Finally you square the number of years by the N.