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Mathematics

2 answers:

netineya [11]3 years ago

7 0

The second choice in the second row is the answer

Scrat [10]3 years ago

6 0

I think it’s b but possibly d

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A football team charges $30 per ticket and averages 20,000 people per game. Each person spend an average of $8 on concessions.Fo

olya-2409 [2.1K]

The ticket price that would maximize the total revenue would be $ 23.

Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:

20,000 x 30 + 20,000 x 8 = 760,000
24,000 x 25 + 24,000 x 8 = 792,000
28,000 x 20 + 28,000 x 8 = 784,000
26,000 x 22.5 + 26,000 x 8 = 793,000
27,200 x 21 + 27,200 x 8 = 788,000
26,400 x 22 + 26,400 x 8 = 792,000
25,600 x 23 + 25,600 x 8 = 793,600
24,800 x 24 + 24,600 x 8 = 792,000

Therefore, the ticket price that would maximize the total revenue would be $ 23.

Learn more in brainly.com/question/7271015

4 0

3 years ago

Please help me with this!..

Maru [420]

A represents 12!
12! = 12 * 11 * 10 * 9 * ... (down to 1)

8 0

3 years ago

I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an

Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

$\mu = 0 - 5 = -5$