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seraphim [82]
3 years ago
5

I don't know how to work out the equation below

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
3(x + 4) = 27

First, since our variable is already on one side by itself, we can start out by dividing each side by 3.
x + 4 =  \frac{27}{3}

Second, we need to simplify our fraction we just got. To do so, think of it as this way: what times 3 equals 27? Or, (3 × x = 27). Either way, the answer is 9. 
x + 4 = 9

Third, we can remove (subtract) 4 from each side of the problem. This will give us the answer after we subtract it.
x = 9 - 4

Fourth, our last step is to subtract 9 - 4 to get our answer. (9 - 4 = 5), meaning 5 is our answer.

Answer: \fbox {x = 5}
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Answer:

yes it is!!

Step-by-step explanation:

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3 years ago
Please Help me it’s geometry
mote1985 [20]

Answer:

Option C.

Step-by-step explanation:

Given: In \Delta OPQ,m\angle O=107^{\circ},m\angle P=28^{\circ}.

In \Delta OPQ,

m\angle O+m\angle P+m\angle Q=180^{\circ}    (Angle sum property)

107^{\circ}+28^{\circ}+m\angle Q=180^{\circ}

135^{\circ}+m\angle Q=180^{\circ}

m\angle Q=180^{\circ}-135^{\circ}

m\angle Q=45^{\circ}

Now,

m\angle O>m\angle Q>m\angle P

In a triangle, the greatest angle has largest opposite side and smallest angle has smallest opposite side. So, we conclude that

PQ>OP>QO

Therefore, the correct option is C.

7 0
4 years ago
How do you simplify the equation useing like terms: 8r+12p-7-3p
stiks02 [169]

Answer:

8r+9p-7

Step-by-step explanation:

12p-3p=9p

8r+9p-7

7 0
3 years ago
Referring to the figure, find the value of x
asambeis [7]
A scale of 1:50 000 means that every centimetre on the map is equal to 50 000 centimetres (500 metres) in reality.

The distance between two towns on that map is 6cm, therefore in reality there’s 6 * 50 000 = 300 000 centimetres, which is equal to 3 000 metres, which is equal to 3 kilometres.
3 0
3 years ago
Read 2 more answers
A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
finlep [7]

Answer:

Part a) The elevation of the road is 6\°

Part b) The rise is 0.2\ km

Step-by-step explanation:

Part a) What is the elevation of the road to the nearest degree?

Let

y-----> the rise of the road ( vertical distance)

x ----> the run of the road (horizontal distance)

we have

y/x=1/10

we know that

The ratio y/x is equal to the tangent of the angle of the elevation of the road

Let

\theta ---->  angle of the elevation of the road

tan(\theta)=y/x

tan(\theta)=1/10

\theta=arctan(1/10)=6\°

Part b)  If the road is two km long, how much does it rise?

using proportion

1/10=y/2

y=2/10=0.2\ km

3 0
3 years ago
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