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Wittaler [7]
3 years ago
15

Where would n + 3 be located on this number line?

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

it would be three spots to the right

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a cell phone company charges a monthly fee plus a 0.35 for text messages sent they charge 25.00 monthly fee and your bill is 58.
riadik2000 [5.3K]
Hey,

So first we are told that they charg a fixed fee of 25:00 right?That means even if you didn’t send any text messages you still have to pay 25:00.

So first we have to subtract that 25:00 form 58.25 right?This means the rest of the bill is for text messages OK?
So he spent 33.25(this is the answer to the subtraction) on the text messages right?
And for every text he sent he was charged 0.35 right? So we have to divide 33.25 by 0.35 right?
And that gets us 95.

Now we can double check the answer by multiplieng 95 by 0.35 and adding 25.

So th answer is 95

Hope this helps !!
6 0
3 years ago
HELP ASAP!!!!!!!!!!!
mario62 [17]

Answer:

I can't see the picture

Step-by-step explanation:

8 0
2 years ago
Gggggggggggggggggggggggggggggggggggggggg
user100 [1]

My best possible answer choice should be B

5 0
3 years ago
Read 2 more answers
Explain the error in the work and how you might prevent it
Law Incorporation [45]

Answer:

The error is  -12x² - 14x = - 26x² because 12x² and 14x are unlike terms, so we can not add them

To prevent it the dividend must be written as 6x³ + 0x² - 14x + 1

Step-by-step explanation:

<em>In the division, you must arrange the dividend according to the greatest power of the variable, and put 0 as a coefficient of the missing term to avoid adding, unlike terms.</em>

<u>Example:</u>

If the dividend is 3x³ - 2x + 5, then you must write it as 3x³ + 0x² - 2x + 5

Let us solve our question

∵ The dividend is 6x³ + 1 - 14x

→ You must arrange it from the greatest power of x

∴ The dividend is 6x³ - 14x + 1

∵ The term of x² is missing

→ Write it in the dividend with a coefficient of 0

∴ The dividend is 6x³ + 0x² - 14x + 1

The error is the adding of unlike terms

∵ 6x³ - 14x + 1 ÷ 3x + 6 = 2x² and [6x³ - 14x + 1 - 6x³ - (6x³ + 12x²)]

∵ [6x³ - 14x + 1 - 6x³ - (6x³ + 12x²)] = 6x³ - 14x + 1 - 6x³ - 12x²

∵ 6x³ - 14x + 1 - 6x³ - 12x² = 0 - 12x² - 14x + 1

∵ 0 - 12x² - 14x + 1 = -26x² + 1 ⇒ error

∴ The error is  -12x² - 14x = - 26x² because 12x² and 14x are unlike terms,

   so we can not add them

→ To prevent it, write 0 as a coefficient of the missing term

∵ The missing term is the term of x²

∴ Add to the dividend the term 0x²

∴ The dividend must be written as 6x³ + 0x² - 14x + 1

4 0
2 years ago
Read 2 more answers
Simplify: (−7a − 19c) − (−12a + 30c) − (−21a − 11c)
GrogVix [38]
(−7a − 19c) − (−12a + 30c) − (−21a − 11c)

= −7a − 19c + 12a - 30c + 21a + 11c

= (-7a + 12a + 21a) + (11c - 19c - 30c)

= 26a - 38c

= 2(13a - 19c)
8 0
2 years ago
Read 2 more answers
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