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3 years ago

Where would n + 3 be located on this number line?

Mathematics

1 answer:

Naddik [55]3 years ago

6 0

Answer:

it would be three spots to the right

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In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 4x – 5, and HE = 2y + 3. Find the values of x and y.

marissa [1.9K]

Here, DH = HF

x+3 = 3y

x = 3y-3 ----(I)

GH = HE

4x-5 = 2y+3

4x = 2y+8

Substitute value of x,

4(3y-3) = 2y+8

12y-12 = 2y+8

12y-2y = 12+8

10y = 20

y = 2

Now, substitute it in equation 1,

x = 3(2)-3

x = 6-3 = 3

So, your final answer is x=3 & y=2

3 0

3 years ago

Read 2 more answers

If x = 8 units and h = 4 units, then what is the area of the triangle shown above?

Luden [163]

Answer:

D-16 square units

Step-by-step explanation:

Area of a triangle- 1/2 x h x base

8 x4= 32

32/2= 16

5 0

3 years ago

Read 2 more answers

10 cm 8 cm 2.5 cm 8 cm 6 cm 2.5 cm what’s the surface area

DIA [1.3K]

Answer:

10+8+2.5+8+6+2.5=37 .

ok you are understand or bot

6 0

3 years ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

3 years ago

Solve the system of equations by substitution. y=5x-13 5x+2y=19

Assoli18 [71]

x=3‌‌ and ‌‌y=2 to check use the first equation y=5x-13 you plug in x which is 3 5 times 3 equals 15 15-13 equals 2 y=2

8 0

3 years ago