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Nitella [24]
3 years ago
13

Find the total surface area of a cuboidal room whose

Engineering
1 answer:
kolezko [41]3 years ago
5 0

Answer:

Total surface area of cuboid = 174 meter²

Explanation:

Given:

Length of cuboid = 9 meter

Width of cuboid = 5 meter

Height of cuboid = 3 meter

Find:

Total surface area of cuboid

Computation:

Total surface area of cuboid = 2[lb + bh + hl]

Total surface area of cuboid = 2[(9)(5) + (5)(3) + (3)(9)]

Total surface area of cuboid = 2[45 + 15 + 27]

Total surface area of cuboid = 2[87]

Total surface area of cuboid = 174 meter²

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1) When you invest in stock, what are you doing?
statuscvo [17]

<u>Explanation:</u>

1) When we invest in stock it means we are investing in long term investment. It includes risk factor also.

2) We can make money from stocks by retaining them for a long period and selling them when their price rises.

3) dividends are paid out of distributable profits. Some companies provide dividends regularly which act as a regular source of income for investors.

4) Capital gain is the benefit obtained on selling a capital asset and if we face loss on selling the capital asset it results in capital loss. Capital assets are like stock, bonds, properties, etc.

7 0
4 years ago
You have the assignment of designing color codes for different parts. Three colors are used on each part, but a combination of t
Masja [62]

Answer:

7 available

Explanation:

Since 3 colors are available r = 3

Total combination = 35

nCr = 35 ---1

nCr = n!/(n-r)!r!---2

We put equation 1 and 2 together

n-1)(n-2)(n-3)!/n-3)! = 35x 3!

We cancel out (n-3)!

(n-1)(n-2) = 210

7x6x5 = 210

nC3 = 35

7C3 = 35

So If there are 35 combinations, 7 colors are available.

Thank you!

3 0
3 years ago
Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an
Lera25 [3.4K]

Answer:

\dot Q_{out} = 13369.104\,kW

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0

The rate of heat transfer between the turbine and its surroundings is:

\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}

The specific enthalpies at inlet and outlet are, respectively:

h_{in} = 3076.41\,\frac{kJ}{kg}

h_{out} = 2675.0\,\frac{kJ}{kg}

The required output is:

\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW\dot Q_{out} = 13369.104\,kW

4 0
3 years ago
What is technology and what are the four features of technology?
MAXImum [283]

Answer: Technology is the application of scientific knowledge for practical purposes, especially in industry.

Mechanical.

Electronic.

Industrial and manufacturing.

Medical.

Communications.

Explanation:

7 0
3 years ago
Read 2 more answers
Cryogenic liquid storage. Liquid oxygen is stored in a thin-walled spherical container, 96 cm in diameter, which is further encl
Anvisha [2.4K]

Answer:

The answer is "26.55 V"

Explanation:

Given values:

d_i= 0.96m\\d_o= 1m\\\epsilon = 0.05\\T_0= 280k\\T_i= 95k\\

For Answer  (a) please find the attachment.

Answer (b):

q_{i-0}= \frac{\sigma (T_{0}^4)-(T_{i}^4)}{\frac{1-\epsilon i }{\epsilon_{i} A_{i}}+ \frac{1 }{\ f_{i o} A_{i}} +\frac{1-\epsilon_{0}}{\epsilon_{0} A_{0}}}

f_{i0}= 1 \ it \ is \ fully \ inside \ the \ large \ sphero \\

q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}} - 1+ 1 +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times \frac{A_i}{A_0}}\\\\q_{i-0}= \frac{\sigma A_i (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}}  +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{d_i}{d_0})^2}\\\\q_{i-0}= \frac{\sigma (\pi d^2_i) (T_{0}^4)-(T_{i}^4)}{\frac{1 }{\epsilon_{i}}  +\frac{1-\epsilon_{0}}{\epsilon_{0}} \times (\frac{r_i}{r_0})^2}\\\\

q_{i-0}= \frac{5.67 \times 10^{-8} \times 3.14 \times 9.62 \times 9.62 \times (280^4-94^4)}{\frac{1 }{0.05}  +\frac{1-0.05}{0.05} \times (\frac{0.96}{1})^2}\\\\\ After \ solve the \ equation \ the \ answer \ is:\\\\q_{i-0} = 26.55 \ V

4 0
3 years ago
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