Answer:
The torque on the section is 563.373 Nm
Explanation:
The torque in the section can be calculated through torsion formula. The torsion formula is given as follows:
Torque = T = τJ/ r
where,
r = maximum radius = 5.5 cm/2 = 2.75 cm = 2.75 x 10^-2 m
τ = maximum shear stress = 22 MPa = 22 x 10^6 Pa
J = Polar moment of inertial = π/2 (ro^4 - ri^4)
J = π/2 (0.0275^4 - 0.01875^4) m^4 = 7.042 x 10^-7 m^4
Therefore:
T = (7.042 x 10^-7 m^4)(22 x 10^6 Pa)/(2.75 x 10^-2 m)
<u>T = 563.373 Nm</u>
Answer:
it is not possible to place the wires in the condui
Explanation:
given data
total area = 2.04 square inches
wires total area = 0.93 square inches
maximum fill conduit = 40%
to find out
Can it is possible place wire in conduit conduit
solution
we know maximum fill is 40%
so here first we get total area of conduit that will be
total area of conduit = 40% × 2.04
total area of conduit = 0.816 square inches
but this area is less than required area of wire that is 0.93 square inches
so we can say it is not possible to place the wires in the conduit
Answer:
Explanation:
The concept of amperes law is applied;
Given the current density vector in the medium is J,
the electric flux density vector is D,
and the magnetic flux density vector is B. The line integral of the magnetic field intensity H
considering the orientation of the contour is adopted according to ampere law;
deta x B = Jc + JD
delta x B = Jc + partial differential D/partial differential t
where Jc = conduction current density
JD = displacement current density
Answer:answer is part a 100 x
Explanation:
We know that a prefix of Mega(M) is used for a quantity of
numbers thus 100 MW = 100 x