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Dahasolnce [82]
2 years ago
13

What is the base unit in standard measurement

Engineering
2 answers:
Stella [2.4K]2 years ago
7 0

Answer:

Explanation:SI is the base unit for standard measurement

Brut [27]2 years ago
6 0
SI is the base standard measurement
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All of these are true about a magnesium part EXCEPT that it:
d1i1m1o1n [39]

The option that is an exception about the properties of magnesium is the option;

<u>Is typically made from </u><u>stampings</u>

The reason why the option is an exception is given as follows:

  • Magnesium is a nonferrous metal as it is usually combined with manganese, zinc and aluminum.

  • Within the group of structural metals, magnesium is the lightest, having  a high strength-to-weight ratio.

  • Magnesium posses good dampening characteristics, and is capable of reducing vibration of mechanical parts.

<em />

<em>However</em>

  • Magnesium parts used for vehicle construction are die cast, and not made from stampings because magnesium is more difficult to stamp compared to aluminum.

Therefore, the correct option for the statement that is an exception from the true statements about magnesium is magnesium; <u>is typically made from stampings</u>

Learn more about the properties of magnesium here:

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brainly.com/question/5106448

8 0
2 years ago
How are scientific discoveries used in engineering design?
Citrus2011 [14]

Answer:

one is technology

6 0
3 years ago
While discussing run-flat tires: Technician A says that some are self-sealing tires and are designed to quickly and permanently
musickatia [10]

Answer:

The correct option is d ( Neither A nor B)

Explanation:

Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.

Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.

This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong

Since option a and b are incorrect and c is invalid.

4 0
2 years ago
function summedValue = SummationWithLoop(userNum) % Summation of all values from 1 to userNum summedValue = 0; i = 1; % Write a
Alexeev081 [22]

Answer:

function summedValue = SummationWithLoop(userNum)

% Summation of all values from 1 to userNum

  summedValue = 0;

  i = 0;

  % use a while loop that assigns summedValue with the

  % sum of all values from 1 to userNum

  while(i <= userNum)

      summedValue = summedValue + i;

      i = i + 1;

  end

end

8 0
3 years ago
The mass flow rate in a 4.0-m wide, 2.0-m deep channel is 4000 kg/s of water. If the velocity distribution in the channel is lin
IceJOKER [234]

Answer:

V = 0.5 m/s

Explanation:

given data:

width of channel =  4 m

depth of channel = 2 m

mass flow rate = 4000 kg/s = 4 m3/s

we know that mass flow rate is given as

\dot{m}=\rho AV

Putting all the value to get the velocity of the flow

\frac{\dot{m}}{\rho A} = V

V = \frac{4000}{1000*4*2}

V = 0.5 m/s

4 0
3 years ago
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