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Ber [7]
3 years ago
12

Pls help me I really don’t know

Mathematics
1 answer:
lord [1]3 years ago
5 0

Answer:

1232    =>      1

2464    =>     2

6160    =>      5

9856   =>      8

Step-by-step explanation:

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34 points <br><br> -2[3x-(b+2x)+(x-3b)]<br><br> plz show steps i'm stuck
natali 33 [55]
First,multiply the -2 by everything in the brackets
so that's, -6x-(b-4x)+(x+6b)
then combine like terms
that's -6x-(7b-3x) which is
-3x-7b I believe
5 0
3 years ago
Whats the anwer anybody tell me
Olenka [21]

Formula for the area of a circle: A = pi x r^2

Solve for the radius:

36pi = pi x r^2

r^2 = 36

r = 6 cm

Hope this helps! :)

7 0
3 years ago
Read 2 more answers
Question 8 of 10
jekas [21]

Answer:

What are the choices?

Step-by-step explanation:

4 0
4 years ago
A student collected monetary pledges for a fundraiser. One donor pledged to contribute $5 for each mile walked by the student du
Snezhnost [94]

Answer:

A. The situation is discrete B. i. { x : 0 ≤ x ≤ 6; x ∈ Z} ii. { C = 5x : 0 ≤ C ≤ 30; C ∈ Z}

Step-by-step explanation:

A. The situation is discrete since we have integral values for the amount paid per mile walked. The amount per mile is $5 and is only paid if a complete mile is walked. So, it is a discrete situation.

B. i. Since 0 miles represents 0 distance and the student walks a maximum of 6 miles, let x represent the distance walked. So the domain is 0 ≤ x ≤ 6 where x ∈ Z where Z represent integers.

{ x : 0 ≤ x ≤ 6; x ∈ Z}

ii. Since at 0 miles the amount earned is 0 miles × $5 per mile = $ 0 and at the maximum distance of 6 miles, the amount earned is 6 miles × $5 per mile = $ 30, let C represent the amount donated in dollars. So the range is 0 ≤ C ≤ $ 30 where C = 5x.

{ C = 5x : 0 ≤ C ≤ 30; C ∈ Z}

6 0
3 years ago
lagrange multiplier what are the points on the intersection of the ellipsoid with the plane that are respectively closest and fu
sleet_krkn [62]

The points on the intersection of the ellipsoid with the plane that are respectively closest and furthest from the origin are

(2–√,−2–√,2−22–√)

(−2–√,2–√,2+22–√)

Using Lagrange multipliers we attempt to find the extrema of f(x,y,z)=x2+y2+z2 given that g(x,y,z)=x−y+z−2=0 and that h(x,y,z)=x2+y2−4=0.

Given,

∇f=⟨2x,2y,2z⟩

∇g=⟨1,−1,1⟩

∇h=⟨2x,2y,0⟩

Extrema satisfy the condition that ∇f=μ∇g+λ∇h for some λ,μ∈R.

This is to say,

2x=2λx+μ

2y=2λy−μ

2z=μ

If λ=1 then μ=0 and so z=0, the g constraint tells us that x=y+2, and the h constraint tells us that y2+(y+2)2=4, meaning that either y=0 or y=2. This provides us with two crucial points in addition to the g constraint:

(2,0,0)

(0,−2,0)

Now assume λ≠1, and so

x=μ2−2λ

y=−μ2−2λ=−x

Since x=−y, we have that x=±2–√, y=∓2–√. Using the g constraint, our two critical points are

(2–√,−2–√,2−22–√)

(−2–√,2–√,2+22–√)

And then it's east to determine which is the max and which is the min out of these four critical points.

To learn more about Lagrange multiplier

brainly.com/question/4609414

#SPJ4

3 0
2 years ago
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