Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
Convert it then you will fine the weight.
Answerd
Step-by-step explanation:
13pulgadas
2.6* 5=13
Let the partitions of the segment be 5k and 3k .
.
5k+3k = length of segment
Suppose the length of segment is y
8k = y
k = y/8
.
Hence ,
5k = 5(y/8)
3k = 3(y/8)
.
As the value of the segment wasn't given , it seems a bit complicated..
.
Hope u understand!
Answer:
x=16/3=5.33.
Step-by-step explanation:
Isolate x on one side of the equation.
2+x3=18
2+x*3=18
2+x*3-2=18-2 (First, subtract 2 from both sides.)
18-2 (Solve.)
18-2=16
x*3=16
x*3/3=16/3 (Then, divide by 3 from both sides.)
16/3=5.33
x=16/3=5.33
In conclusion, the final answer is x=16/3=5.33.
