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grandymaker [24]
3 years ago
15

A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v

elocity of 10.0 m/s due north relative to the water. If the river is 325 m wide, how far downstream is the boat when it reaches the north shore?
Physics
1 answer:
Ann [662]3 years ago
6 0

Answer:

Explanation:

Given that the velocity of the river is 1.50m/s due east.

The velocity of the boat with respect to the river is 10.0 m/s due north .

The width of the river is 325 m.

Note that the velocity of the boat will help in crossing the river.

Hence, speed = distance/time

Speed = 10.0 m/s

Distance = 325 m

Time = ?

10 = 325/time

Time = 325/10

Time = 32.5s

Hence in 32.5s the horizontal distance traveled by boat will be

= 1.50m/s × 32.5s

= 48.75m

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The basketball coach tells his team to run sprints back and forth across the court, which is 30 m long. They start at the left e
sp2606 [1]

Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.


The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.


The end point is the same as the starting point, so the displacement is 0 m.

5 0
3 years ago
Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface. When she lands on Noveria, a distant planet in
Anastasy [175]

Answer:

Acceleration of gravity on Noveria = 4.4 m/s²

Explanation:

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface.

We have weight, W = mg

Acceleration due to gravity, g = 9.81m/s²    

799 = m x 9.81

Mass of Shepard, m = 81.45 kg            

She lands on Noveria, a distant planet in our galaxy, she weighs 356 N.

We have weight, W = mg'

                 356 = 81.45 xg'

Acceleration of gravity on Noveria, g' = 4.4 m/s²

6 0
4 years ago
Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-deg
n200080 [17]

Answer:

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N

Thus, the net force over the body is:

F=(913.14N)\hat{i}+(274.87N)\hat{j}

Next, you calculate the magnitude of the force:

F=\sqrt{(913.14N)+(274.87N)^2}=953.61N

and the direction is:

\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°

7 0
3 years ago
If a canadian plane is traveling at 500 miles/hr, how fast is this in m/s?
patriot [66]
223.52 meters per second
6 0
4 years ago
How much time will it take to do 33j of work with 11 w of power
Yuri [45]

Time required : 3 s

<h3>Further explanation </h3>

Power is the work done/second.

\tt P=\dfrac{W}{t}\\\\P=power,j/s,watt\\\\W=work, J\\\\t=times=s

 

To do 33 J of work with 11 W of power

P = 11 W

W = 33 J

\tt t=\dfrac{W}{P}\\\\t=\dfrac{33}{11}\\\\t=\boxed{\bold{3~s}}

8 0
4 years ago
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