Answer
given,
length of rod = 21.5 cm = 0.215 m
mass of rod (m) = 1.2 Kg
radius, r = 1.50
mass of ball, M = 2 Kg
radius of ball, r = 6.90/2 = 3.45 cm = 0.0345 m
considering the rod is thin
![I = \dfrac{1}{3}M_{rod}L^2 + [\dfrac{2}{5}M_{ball}R^2+M_{ball}(R+L)^2]](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B1%7D%7B3%7DM_%7Brod%7DL%5E2%20%2B%20%5B%5Cdfrac%7B2%7D%7B5%7DM_%7Bball%7DR%5E2%2BM_%7Bball%7D%28R%2BL%29%5E2%5D)
![I = \dfrac{1}{3}\times 1.2 \times 0.215^2 + [\dfrac{2}{5}\times 2 \times 0.0345^2+2\times (0.0345 +0.215)^2]](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%201.2%20%5Ctimes%200.215%5E2%20%2B%20%5B%5Cdfrac%7B2%7D%7B5%7D%5Ctimes%202%20%5Ctimes%200.0345%5E2%2B2%5Ctimes%20%280.0345%20%2B0.215%29%5E2%5D)
I = 0.144 kg.m²
rotational kinetic energy of the rod is equal to


KE = 6.15 J
b) using conservation of energy



ω = 9.25 rad/s
c) linear speed of the ball
v = r ω
v = (L+R )ω
v = (0.215+0.0345) x 9.25
v =2.31 m/s
d) using equation of motion
v² = u² + 2 g h
v² = 0 + 2 x 9.8 x 0.248
v = √4.86
v =2.20 m/s
speed attained by the swing is more than free fall
% greater = 
= 5 %
speed of swing is 5 % more than free fall
The strength of the gravitational force between two objects depends on the distance between their centers.
At higher altitude, the center of the Earth is farther from the center of YOU, so the strength of the gravitational force between those two objects is less.
Answer:
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
Explanation:
Given that distance between Salem and Vernonville = 160 miles
Lest take speed of car which leaves from Vernonville = V miles per hour
So the speed of car which leaves from Salem = V +10 miles per hour
These two car meet at time = 1 hr 36 min = 1.6 hr
Distance travel by car leaves from Salem = x
x= (V+10) x 1.6 --------1
Distance travel by car leaves from Vernonville = 160 - x
160 - x= V x 1.6 ----------2
From equation 1 and 2
160 - (V+10) x 1.6 = V x 1.6
V= 45 miles per hour
So
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
Explanation:
Initial speed of the incident water stream, u = 16 m/s
Final speed of the exiting water stream, v = -16 m/s
The mass of water per second that strikes the blade is 48.0 kg/s.
We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :

Here, 

So, the magnitude of the average force exerted on the water by the blade is 1536 N.