Answer:
Em₀ = U = m g h
, Em_{f} = K = ½ m v²
Explanation:
When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by
Em₀ = U = m g h
As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy
Em = K + U = ½ m v² + mg y
y <h
when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy
Em_{f} = K = ½ m v²
This energy transformation is in the case that the friction force is zero.
If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor
= - fr L
therefore the numeraire values of the velocity are lower, due to the energy lost by friction.
Answer:
6 V
Explanation:
We can solve the problem by using Ohm's law:
where
V is the voltage in the circuit
R is the resistance
I is the current
In this problem, we know the current, 
, and the resistance, 
, therefore we can find the voltage in the circuit:
Answer:
Secondary voltage on second transformer is 200 volt.
Explanation:
It is given two transformer
Let us consider first transformer.
Number of turns in primary 
Numb er of turns in secondary 
Now consider second transformer
Number of turns in primary 
Number of turns in secondary 
Now it is given that same voltage of 50 volt is applied to primary of both the transformer.
For second transformer
So secondary voltage on second transformer is 200 volt
C. Usually when an atom loses or gains an electron, it is because it is trying to satisfy the Octet Rule. The Octet Rule states that an atom is at its stablest when it has 8 valence electrons (two in helium's case)
If you look on the periodic table, elements on the left (Alkaline Metals) are the most reactive because they only have one valence electron (or electron in the outer shell). Elements on the right (Noble Gases) are the least reactive because they have a full outer shell of 8 valence electrons.
Later on you will find that as stability decreases as you go down the periodic table but that is a discussion for a different time.
Answer:
a) d = 30.79 m
, b) θ = -22.4°
, θ = 22.4 South of East
Explanation:
The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis
Let's use the index for / Ricardo and the index for Jane, let's break down the displacements
Richard
X axis
x₁ = 26.0 sin (60)
x₁ = -22.52 m
Y Axis
y₁ = 26.0 cos 60
y₁ = 13 m / s
Jane
X axis
x₂ = 16.0 cos (180 +30)
x₂ = -13.85 m
Y Axis
y₂ = 16.0 sin (180 + 30)
y₂ = - 8.0 m
Now we can use Pythagoras' theorem to find the distance between them
d = √ [(x₂ -x₁)² + (y₂ -y₁)²]
d = √ [(-13.85 + 22.52)² + (-8 -13)²]
d = 30.79 m
Let's use trigonometry to enter the address
tan θ = Δy / Δx
θ = tan⁻¹ Δy / Δx
θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)
θ = tan⁻¹ (-8.67 / 21)
θ = -22.4°
The negative sign indicates that the angle is measured from the axis clockwise.
In the form of cardinal s point is
θ = 22.4 South of East
