Answer:
displacement = 2 m west
Explanation:
The displacement of an object is a vector connecting the final point of the motion of the object to the initial point, and its magnitude is equal to the length of the vector. So the magnitude of the displacement is basically the distance (measured in a straight line) between the final point and the starting point.
In this problem, we have:
- initial position of the acorn: 0 m
- final position of the acorn: 2 m west
So, the displacement has a magnitude of
d = 2 m - 0 m = 2 m
And the direction is west, since the final position is west compared to the initial position.
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :

v is image distance

Magnification,

So, the magnification of the lens is 3.
Answer:
Option B. N2(g) + 3H2(g) → 2NH3(g)
Explanation:
When nitrogen react with hydrogen, they form a product as shown below:
N2+ H2 → NH3
We need to balance the equation. This is illustrated below:
There are 2 atoms of nitrogen on the left side and 1 atom on the right side. To balance it, put 2 in front of NH3 as shown below:
N2+ H2 → 2NH3
Now, There are a total of 6 atoms of Hydrogen on the right side and 2 atoms on the left side side. This can be balanced by putting 3 in front of H2 as shown below:
N2+ 3H2 → 2NH3
Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation
Answer:
v = 40 [m/s].
Explanation:
Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

where:
m = mass [kg]
v = velocity [m/s]
![P =20*10\\P =200 [kg*m/s]](https://tex.z-dn.net/?f=P%20%3D20%2A10%5C%5CP%20%3D200%20%5Bkg%2Am%2Fs%5D)
Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.
![v = P/m\\v = 200/5\\v = 40 [m/s]](https://tex.z-dn.net/?f=v%20%3D%20P%2Fm%5C%5Cv%20%3D%20200%2F5%5C%5Cv%20%3D%2040%20%5Bm%2Fs%5D)
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />
According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.
Now, in this case we are on Earth, so the gravity value is
Note the objects experience the acceleration of gravity regardless of their mass.
Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely true on Earth, unless the following condition is fulfiled:
If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at
and hit the ground at approximately the same time.