Answer:
C. Approximately normal
Step-by-step explanation:
We know that when we have, np≥10, and n(1−p)≥10, and both of these are true, where n is the sample size, and p is the sample of proportions, the sampling proportions of sample distributions, will be normal in shape.
Expected successes : np=125(0.88)=110≥10
Expected failures : n(1−p)=125(1−0.88)=15≥10
Answer:
The equation wants you to solve for the term 'nz', as these two terms when multiplied represents the amount of party favors in the boxes. We are already given the following equation:
Multiply both sides by f to get nz by itself. The following equation will be your answer:
Answer:
25 minutes
Step-by-step explanation:
Worker1 is filling up at a rate of 11 per minute while worker2 is filling up at a rate of 11+1 per minute. Since worker1 has 25 extra barrels and since worker2 makes one extra barrel per minute it will take exactly 25 minutes to match worker1's barrel count.
Answer:
Below in bold.
Step-by-step explanation:
Mean = (98+92+90+78+83+88+95)/7
= 89.1 to nearest tenth.
Deviations:
98 - 89.1 = 8.9
92 - 89.1 = 2.9
90 - 89.1 = 0.9
78 - 89.1 = -11.1 = 11.1 (absolute value)
83 - 89.1 = 6.1
88-89.1 = 1.1
95 - 89.1 = 5.9
So the MAD
= (8.9+2.9+0.9+11.1+6.1+1.1+5.9)/7
= 36.9/7
= 5.27
= 5.3 to nearest tenth.