Answer:
C. Approximately normal
Step-by-step explanation:
We know that when we have, np≥10, and n(1−p)≥10, and both of these are true, where n is the sample size, and p is the sample of proportions, the sampling proportions of sample distributions, will be normal in shape.
Expected successes : np=125(0.88)=110≥10
Expected failures : n(1−p)=125(1−0.88)=15≥10
