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joja [24]
2 years ago
5

Least common multiple of 35 and 70

Mathematics
2 answers:
Angelina_Jolie [31]2 years ago
4 0

【Answer】The least common multiple of 35 and 70 is 70.

                          \orange{ {\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedure}}{\hspace{50pt}\above 1.2pt}}                        

To obtain the least common multiple (lcm) we must do it by simultaneous decomposition.

This method consists of extracting the common and uncommon prime factors, then

\large\displaystyle\text{$\begin{gathered}\sf \left.\begin{matrix} \blue{35 \ \ \ 70}\\ 35 \ \ \ 35\\ 7 \ \ \ \ 7\\  1 \ \ \ \ 1 \end{matrix}\right|\begin{matrix} 2\\ 5\\ 7\\ \: \end{matrix} \end{gathered}$}

                                        \sf{L.c.m.(35,70)=2\times5\times7}

                                          \boxed{\boxed{\sf{L.c.m.(35,70)=70}}}

<h2>{ Pisces04 }</h2>

Andreas93 [3]2 years ago
3 0

Answer:

70

Step-by-step explanation:

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What is the measurement of angle P? MPO O A.) 36° O B.) 64° O C.) 116° O D.) 244°​
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One endpoint of a line segment has coordinates represented by (x+4,1/2y). The midpoint of the line segment is (3,−2).
lesya692 [45]

Answer:

(-x+2, -\frac{1}{2}y-4})

Step-by-step explanation:

We know that one of the endpoints of the line segment is (x+4, 1/2y)

The midpoint of the line segment is (3, -2).

And we want to find the other coordinates in terms of x and y.

To do so, we can use the midpoint formula:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since we know that the midpoint is (3, -2), let's substitute that for M:

(3, -2)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let's solve for each coordinate individually:

X-Coordinate:

We have:

3=\frac{x_1+x_2}{2}

We know that one of the endpoints is (x+4, 1/2y). So, let's let (x+4, 1/2y) be our (x₁, y₁). Substitute x+4 for x₁. This yields:

3=\frac{(x+4)+x_2}{2}

Solve for our second x-coordinate x₂. Multiply both sides by 2:

6=x+4+x_2

Subtract 4 from both sides:

2=x+x_2

Subtract x from both sides. Therefore, the x-coordinate of our second point is:

x_2=-x+2

Y-Coordinate:

We have:

-2=\frac{y_1+y_2}{2}

Substitute 1/2y for y₁. This yields:

-2=\frac{\frac{1}{2}y+y_2}{2}

Solve for y₂. Multiply both sides by 2:

-4=\frac{1}{2}y+y_2

Subtract 1/2y from both sides. So:

y_2=-\frac{1}{2}y-4

Therefore, the other coordinate expressed in terms of x and y is:

(-x+2, -\frac{1}{2}y-4})

3 0
2 years ago
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