The answer is the second option.
Answer
First we add all of the students that take either algebra 1, algebra 2 or both: 14+20+7= 41 which means out of 60 students 41 take either algebra 1, algebra 2 or both to find the rest of the students we subtract 41 from 6060-41= 19 answer: 19 students don't take either subject
Answer:
30%
Step-by-step explanation:
Before starting to solve this question we have to understand the following. 1% is equal to one hundredth of something whole, and can be write as .
Now in order to solve this question we will first have to find a fraction that represent how much student out of the whole class choose hamburgers. We can easily find this fraction since the numerator of the fraction will be equal to the number of people that choose hamburgers and the denominator will be equal to the number of all students in the class. So we get......
Now in order to find out what percentage will this fraction equal to we will have make a fraction with the same value but with a denominator being 100. To do that we will have to understand the following......
(m is any number except 0)
The main I idea of this rule is that if we multiply the numerator and the denominator by the same number (any number except 0) we will get a fraction with the same value but with a different denominator and numerator.
So in our case we we do the following.........
(multiply both numerator and the denominator by 10 and we get...)
Now if we go back to what I said at the start of my explanation we will understand that another way of writing down is 30%.
Answer:
Answer: (7,-2)
Step-by-step explanation:
Look at the formula
1) (x – h)^2 + (y – k)^2 = r2
the center is described by (h,k)
now look at
(x – 7)^2 + (y +2)^2 = 25
here h=7
but k= -2 because is (y+2) =(y-(-2))
Answer:
Write the written problem into an equation to get:
3x +2 = 5x -4
To solve:
Add 4 to each side:
3x+6 = 5x
Subtract 3x from each side:
2x = 6
Divide both sides by 2:
x = 6/2
x = 3
Step-by-step explanation: