All categories

3 years ago

4.50 +0.50R = 10 Inequalities

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

8 0

Answer:

what does not equal 10

Step-by-step explanation:

topjm [15]3 years ago

6 0

That doesn’t equal 10 it equals r=11

You might be interested in

What is the slope of the line shown below?<br> y=1/3x-3

inysia [295]

Answer:

slope=1/3

Step-by-step explanation:

the equation is in slope-intercept form (y=mx+b) and m always equals slope in that equation, so in your equation m=1/3, so slope=1/3

5 0

3 years ago

Select the solutions of the equation. <br> 2x2-3x-5=0

meriva

Using the Quadratic formula

your answer would be A and C

5 0

3 years ago

Read 2 more answers

C= 5/9 (F−32)

Grace [21]

Answer:

C = 5/9 (F - 32)

This is a temperature scale change comparison.

By this we understand, that ,

1°C = 5/9°F

Which is equal to, 5/9°F = 1°C

These two statements are satisfied by I. and II.

So, the correct answers are, I. and II.

If my answer helped, kindly mark me as the brainliest!

Thank You!!

5 0

3 years ago

Will give brainiest algebra 2

mars1129 [50]

The sum of squares of numbers is: 13

Step-by-step explanation:

Let x and y be two numbers

Then,

Difference of the squares of the numbers will be:

$x^2-y^2$

Product will be:

$xy$

Given identity is:

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Given values are:

Difference of the squares of the numbers= $x^2-y^2=5$

Product of numbers = xy = 6

Putting the values in the identity

$(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169$

As we have to only find x^2+y^2

Taking square root on both sides

$\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13$

The sum of squares of numbers is: 13

Keywords: Identities

Learn more about identities at:

#LearnwithBrainly

7 0

3 years ago

The sum ∫2−2() ∫52()−∫−1−2() can be written as a single integral in the form ∫() determine and

kow [346]

We have

$\displaystyle \int_{-2}^2 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx = \int_{-1}^2 f(x) \, dx$

so that

$\displaystyle \int_{-2}^2 f(x) \, dx + \int_2^5 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx \\\\ ~~~~~~~~~~~~ = \int_{-1}^2 f(x) \, dx + \int_2^5 f(x) \, dx \\\\ ~~~~~~~~~~~~ = \boxed{\int_{-1}^5 f(x) \, dx}$

6 0

1 year ago