Answer:
Step-by-step explanation:
step a system of two equations c = child ticket a = adult ticket
eq 1) 2c + 1a = 8.2 multiply by 2
eq 2) 3c + 2a = 14.1
I will multiply eq 1 times TWO and subtract eq 2 from eq 1a)
eq 1a) 4c + 2a = 16.4
eq 2) 3c + 2a = 14.1
subtract (4c - 3c) + (2a -2a) = 16.4 - 14.1
c + 0 = 2.3 euros for one child ticket
Now find the adult ticket price, plug 2.3 for c into eq 1)
eq 1) 2c + 1a = 8.2
eq 1) 2(2.3) + 1a = 8.2 solve for a
4.6 + a = 8.2 substract 4.6 from both sides
a = 8.2 - 4.6
= 3.6 euros for one adult ticket
double check using eq 2) we know c and a values
eq 2) 3c + 2a = 14.1
eq 2) 3(2.3) + 2(3.6) = 14.1
6.9 + 7.2 = 14.1
14.1 = 14.1
2[(∛8)²+1/8*16]
(∛8)² = (∛8) x (∛8) = (∛64) = 4
1/8 *16 = 16/8 = 2
Total expression = 2 * (4+2)= 12
