<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3
</span>where ((<span>y^2 * y)) adding the powers in case of multiplication
and also for this:</span><span> (<span>x^2*x)</span> </span>
Answer:
a) 0.125
b) 0.015635
c) 0.00000095367431640625
Step-by-step explanation:
a) 
b) 
c) 
Answer:
97.3%
Step-by-step explanation:
Let the three bulbs be A, B and C respectively.
Let P(A) denote the probability that the first bulb will burn out
Let P(B) denote the probability that the second bulb will burn out
Let P(C) denote the probability that the third bulb will burn out
Now, we are told that Each one has a 30% probability of burning out within the month.
Thus;
P(A) = P(B) = P(C) = 30% = 0.3
Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;
P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))
P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%
Answer:
2,000 is the value of the digit 2 in the thousands place
Question 10: P=28cm
if l=8 and w=6
Then (8+6)=14
2(14) so 14x2 = 28
So therefore P=28cm
