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artcher [175]
3 years ago
9

Take points for free who are new and enjoye them

Computers and Technology
2 answers:
Schach [20]3 years ago
6 0

Answer:niceeeee

Explanation:

bearhunter [10]3 years ago
3 0

This has been up for a week, and I don't know how nobody answered it, but tysm! :D

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An interface is a class that contains only the method headings and each method heading is terminated with a semicolon. True Fals
liubo4ka [24]

Answer:

False

Explanation:

Interfaces are similar to classes in Java, but they are not a type of class. A class defines the attributes and behaviours of objects, while interface contains the methods that shows the behaviours to be implemented by a class.

A method is one or more group of statements, it does not need to end with a semicolon. Methods in interfaces are abstract and for a class to contain these abstract method, it must be defined in the class.

3 0
3 years ago
Louis has entered a column of expense values. What feature can he use to insert the total expenses at the end of the column?
vovangra [49]
I think it’s B tho I’m not really sure
5 0
3 years ago
What does cramming to hand in an assignment
Vikki [24]
Honestly gotta say cramming in an assignment doesnt help at all

5 0
3 years ago
In most signal "timing diagrams" (like the one below) the signals do not change from low to high, or from high to low, abruptly.
melisa1 [442]

Explanation:

This transient state occurs due to the fact that the signal change from low to high and high to low doesn't occur intermediately but in a very small time, in relation to the signal time itself.

At transistor level there are parasitic (undesired) capacitances and resistances, formed due to the layout configuration of conductor and dielectrics. As consequence a RC circuit is formed, thus making a propagation delay.

This delay must be characterized for each circuit, and specified as tpHL (transition time from High to Low) and tpLH (transition time from Low to High)

8 0
3 years ago
Create the Following Menu in a loop so the menu will continually show until the user chooses to exit.AddMultiplyExitAdd a value
ycow [4]

Answer:

I have added the code again with the mistakes are corrected please see the comments in code. You have mistake in while loop condition.

#include <iostream>

#include <iomanip>

#include <cmath>

using namespace std;

int options ();

int option1 ();

int option2 ();

int option3 ();

double addition (double num1, double num2);

double multiplication (double num1, double num2);

int main()

{  

jump:

int option = 0;  

cout << "1. Add" << endl;

cout << "2. Multiply" << endl;

cout << "3. Exit" << endl;

 cout << "Enter option 1 for addition, option 2 for multiplication, or option 3 to exit" "Enter an option: ";

  cin >> option;

   switch (option)  

{  

case 1:option1;  

int option1 ();

{  

double num1 = 0;  

double num2 = 0;

// void int key = 0;  

cout << " Enter a number: ";  

cin >> num1;  

cout<< " Enter a second number: ";  

cin >> num2;  

double sum = addition(num1, num2);  

cout << " Sum is: " << sum <<endl;

 } break;  

 case 2: option2;  

 int option2 ();

 {  

 double num1 = 0;  

 double num2 = 0;

 cout << " Enter a number:";

 cin >> num1;

 cout << " Enter a second number: ";

 cin >> num2;

 double product = multiplication(num1, num2);

  cout << " Product is: " << product << endl;

  //system("cls");

  }  

  break;

   case 3: option3;  

   int option3();

    {

 return 0;

 }  

 break;  

 default: cout << " Invalid number entered: ";

 }

 //do {main();}

 //while (option < 3); //you have mistake in this loop please have a look

 while (option<3)

 {

  goto jump;

 }

 

 }

 double addition(double num1, double num2)

 {

  return num1 + num2;

  }

 double multiplication(double num1, double num2)

 {

  return num1*num2;

  }

Explanation:

You can also do this by using goto statement in switch case and menu will be repeated until the user not select to exit and now it will work with the loop as well.

I hope it will help you!

4 0
3 years ago
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