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3 years ago

Is this a function? A) Yes B) No

Mathematics

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

because its arranged in well functional statement

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4(PX+1)=64 what is the value of x in terms of p and what is the value of x when p is -5 ?

Oksana_A [137]

Answer:

x = -3

Step-by-step explanation:

$4(PX+1)=64\\\\p= -5$

Substitute -5 for p in the given equation and solve

$4(-5(x)+1)=64\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\frac{4\left(-5x+1\right)}{4}=\frac{64}{4}\\\\Simplify\\-5x+1=16\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\-5x+1-1=16-1\\\\Simplify\\-5x =15\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\frac{-5x}{-5}=\frac{15}{-5}\\\\Simplify\\x = -3$

4 0

2 years ago

5^(2x-1)+5^(x+1)=250 how do you solve? thank you

zepelin [54]

Answer:

x = 2

Step-by-step explanation:

Exponential Equations

Solve:

$5^{2x-1}+5^{x+1}=250$

Separate each exponential:

$5^{2x}5^{-1}+5^{x}5^{1}=250$

Operating:

$\displaystyle \frac{5^{2x}}{5}+5^{x}5=250$

Multiplying by 5:

$5^{2x}+25\cdot5^x=1250$

Rearranging:

$5^{2x}+25\cdot5^x-1250=0$

Recall that:

$5^{2x}=(5^{x})^2$

$(5^{x})^2+25\cdot5^x-1250=0$

Calling

$y=5^{x}:$

$y^2+25y-1250=0$

Factoring:

$(y-25)(y+50)=0$

There are two possible solutions:

y=25

y=-50

Since

$y=5^{x}$

y cannot be negative, thus:

$5^{x}=25=5^2$

The solution is:

x = 2

8 0

2 years ago

The Gomez family has completed 50% of a trip, They have traveled 40 miles. How far is the trip?

Anettt [7]

Answer: 80 miles

Work: I just did 40 times 2 because they completed half their trip, and they need to complete 40 more miles.

Happy Holidays! :)

4 0

2 years ago

Read 2 more answers

1 /x^−1 in simplest rational form

Allushta [10]

Here is a link to help you find the answer:
https://www.khanacademy.org/math/algebra2/rational-expressions-equations-and-functions/simplify-rati...

Hope this helps!

3 0

3 years ago

Write the answer in interval notation

katovenus [111]

The domain is (-infinity, 6] I believe.

6 0

3 years ago