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vladimir2022 [97]
3 years ago
8

Your boss it trying to console into an old switch that he found in storage and wants to configure it. he asks you to describe wh

at the serial port would look like. what do you tell him?
a. look for a male connector with 7 pins.
b. look for a female connector that accommodates 7 pins.
c. look for a male connector with 9 pins.
d. look for an rj11 interface.

Computers and Technology
2 answers:
nika2105 [10]3 years ago
5 0
I believe that the correct answer is c. look for a male connector with 9 pins.
katrin2010 [14]3 years ago
4 0

Answer:

C) look for a male connector with 9 pins.

Explanation:

Serial ports are male ports, identified as OIO, and they have a 9-pin or a 25-pin connector.

They are still used by some relatively old equipment like point of sales systems and some industrial systems. But they are also used as control consoles for carrying on diagnostics on large server computers.

Serial ports have been replaced by USB ports which are much faster as smaller.

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Answer:

import java.util.Scanner;

public class Program

{

  public static void main(String [] Args)

  {

      int totalAGrades = 0, totalBGrades = 0, totalCGrades = 0, totalDGrades = 0, totalFGrades = 0, counter=0,maximum = 0, minimum = 9999, num, total = 0,smallest = 0,largest = 0;

       Scanner in = new Scanner(System.in);

       System.out.println("Enter exam percentage: ");

       System.out.println("Enter a negative examScore: ");

       int examScore = in.nextInt();

       while(examScore > 0)

       {

         counter++;

         if(examScore < 0){          

             break;}  

         else if(examScore > maximum){      

              maximum = examScore;}

         else if(examScore < minimum)   {  

              minimum = examScore;}

         

          total = total + examScore;  

     

          if(examScore <= 50 && examScore>0)

              smallest = examScore;

              if(examScore > 90 && examScore <=100)

              largest = examScore;

         

      if(examScore>=90 && examScore<=100)

          totalAGrades++;

      else if(examScore>=80 && examScore<=89)

          totalBGrades++;

      else if(examScore>=70 && examScore<=79)

          totalCGrades++;

      else if(examScore>=60 && examScore<=69)

          totalDGrades++;

      else if(examScore>=0 && examScore<=59)

          totalFGrades++;

      examScore = in.nextInt();

     

   }

      System.out.println("Total number of scores is = " + counter );

      System.out.println("Total Number of each Letter grade : " + counter);

      System.out.println("Percentage of total for each letter grade : ");

          System.out.println("Total number of A grades = "+ totalAGrades);

          System.out.println("Total number of B grades = "+ totalBGrades);

          System.out.println("Total number of C grades = "+ totalCGrades);

          System.out.println("Total number of D grades = "+ totalDGrades);

          System.out.println("Total number of F grades = "+ totalFGrades);

     

      System.out.println("Lowest exam Score is :"+smallest);

      System.out.println("Highest exam Score is :"+largest);

      System.out.println("Average exam Score = "+ (total / counter));

  }

}  

Explanation:

  • Get the exam information from user as input and run a while loop until examScore is greater than zero.
  • Use conditional statement to check the scores of students and increment the relevant grade accordingly.
  • Finally display all the information including grades and scores.
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