Question

​Claim: The mean pulse rate​ (in beats per​ minute) of adult males is equal to 69 bpm. For a random sample of 125 adult​ males, the mean pulse rate is 68.3 bpm and the standard deviation is 11.4 bpm. Find the value of the test statistic.

Answer 1

Answer:

0.6865

Step-by-step explanation:

test statistic is given by the formula

test statistic =$\frac{\bar{x}-\mu }{\frac{\sigma }{\sqrt{n}}}$

where $\bar{x}$= mean of the sample

μ= mean

n= sample space

σ= standard deviation

we have given mean of sample  $\bar{x}$ =69

mean μ=68.3

σ=11.4

sample space=125

putting all these value in formula of test statistic

test statistic=$\frac{69-68.3}{\frac{11.4}{\sqrt{125}}}$

=0.6865