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inysia [295]
3 years ago
14

A similarity ratio of scale factor is the ratio of the lengths of the corresponding of two similar polygons

Chemistry
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

go to hellfhshahahahahahahahahaha  aha

Explahhhhahah

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Prepare a list of objects around you that are electroplated​
DedPeter [7]

Answer:

Hello! Some household items that are electroplated include kitchenware, such as metal pots and pans, door handles, mobile phones, and coins. An electroplated object is coated by electrolytic deposition with chromium, silver, or another metal.

8 0
2 years ago
What is the balanced form of the chemical equation shown below?
Tanzania [10]
B. 1, 1, 1, 2
Explanation:
You only need to balance the NaNO3 on the right. Since there is 2 NO3 on the left, you need to put a 2 in front of the NaNO3 on the right. Everything else is already balanced so the only coefficient needed is 2 in front of the NaNO3.
7 0
3 years ago
What is the chemical formula of sulfur dioxide? A. SO B. SO2 C. SO3 D. S2O
Stels [109]
B: SO2
S=Sulfur
O=Oxygen
Dioxide if i am correct means 2 oxygen.
so thats one Sulfur and 2 oxygen.
6 0
3 years ago
Jeffrey is on his skateboard and starts skating down a ramp. Ten seconds later he is travelling at
AfilCa [17]

Answer: 2m/s^2

Explanation:

Velocity of skateboard = 20.0 m/s.

Time taken = Ten seconds (10 s)

Acceleration ​= ?

Recall that acceleration is the change in velocity of a body per unit time.

i.e Acceleration = (velocity / Time)

Acceleration = 20.0m/s ➗ 10 s

Acceleration = 2m/s^2

Thus, Jeffrey acceleration was 2m/s^2

7 0
3 years ago
Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.
Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O

Number of atoms present on reactant side are as follows.

  • C = 1
  • H = 4
  • O = 2

Number of atoms present on product side are as follows.

  • C = 1
  • H = 2
  • O = 3

To balance this equation, multiply O_{2} by 2 on reactant side. Also, multiply H_{2}O by 2 on product side. Hence, the equation can be rewritten as follows.

CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O

Now, the number of atoms present on reactant side are as follows.

  • C = 1
  • H = 4
  • O = 4

Number of atoms present on product side are as follows.

  • C = 1
  • H = 4
  • O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O.

4 0
3 years ago
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