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Anika [276]
3 years ago
11

For the haber process, n2 + 3h2 → 2nh3, what volume of nitrogen is consumed at stp if you collect 44.8 l of ammonia in excess hy

drogen (n = 14 amu, h = 1 amu)?
Chemistry
2 answers:
olasank [31]3 years ago
5 0
Answer is: 22,4 l of nitrogen.
Chemical reaction: 3H₂ + N₂ ⇄ 2NH₃.
V(NH₃) = 44,8 l = 44,8 dm³.
V(N₂) = ?
n(NH₃) = V(NH₃) ÷ Vm
n(NH₃) = 44,8 dm³ ÷ 22,4 dm³/mol
n(NH₃) = 2 mol.
from reaction: n(N₂) : n(NH₃) = 1 : 2
n(N₂) : 2 mol = 1 : 2
n(N₂) = 1 mol.
V(N₂) = n(N₂) · Vm
V(N₂) = 1 mol · 22,4 dm³/mol = 22,4 dm³.
Vm - molar volume
Vesna [10]3 years ago
4 0

Answer:

22.4 L

Explanation:

The other answer has a wonderful explanation. But if you need help, message me :)

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Calculate the mass of each product formed when 84.3 g of silver sulfide reacts with excess hydrochloric acid: ag2s(s) + hcl(aq)
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Answer:

              48.75 g of AgCl

               11.60 g of H₂S

Solution:

The Balance Chemical Equation is as follow,

                                     Ag₂S  +  HCl     →     AgCl  +  H₂S

<u>Calculate amount of AgCl produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  143.32 g (1 mol) of AgCl

So,

                         84.3 g of Ag₂S will produce  =  X g of AgCl

Solving for X,

                      X  =  (84.3 g × 143.32 g) ÷ 247.8 g

                      X  =  48.75 g of AgCl

<u>Calculate amount of H</u><u>₂</u><u>S produced</u><u>,</u>

According to equation,

                247.8 g (1 mol) of Ag₂S produces  =  34.1 g (1 mol) of H₂S

So,

                         84.3 g of Ag₂S will produce  =  X g of H₂S

Solving for X,

                      X  =  (84.3 g × 34.1 g) ÷ 247.8 g

                      X  =  11.60 g of H₂S

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In which group do all atoms have two valence electrons in the ground state?
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