<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Make a bar graph about the length of letters in an animal's name
{3,4,5,6} should be the answer
Answer:
x-int: (3, 0)
y-int: (0, -1.5)
Step-by-step explanation:
x-intercept is the x-value when y = 0
y-intercept is the y-value when x = 0
Step 1: Find x-intercept
0 = (x - 3)/2
0 = x - 3
x = 3
(3, 0)
Step 2: Find y-intercept
y = (0 - 3)/2
y = -3/2
(0, -1.5)
Answer:
254 cm²
Step-by-step explanation:
Calculate first the total area
A = 30*20 = 600 cm²
Then calculate the area of the cercle
A= 10.5²*π = 346.36≈346 cm²
Then substract the area of the circle from the total one:
600-346= 254 cm²
