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Sonbull [250]
3 years ago
10

Chapter 1:Qua

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Answer:

<h3>             (¹/₂, 0)</h3>

Step-by-step explanation:

2x + 5y = 1     ⇒    2x = 1 - 5y

y = 2xy + 5

y = (1 - 5y)y + 5

y = y - 5y² + 5

5y² = 5

y² = 1

 y₁ = 1               ∨           y₂ = -1

2x₁ = 1 -5(1)                   2x₂ = 1 - 5(-1)

2x₁ = 1 - 5                      2x₂ = 1 + 5

2x₁ = -4                         2x₂ = 6

 x₁ = -2                           x₂ = 3

Midpoint:

M=\left(\frac{x_1+x_2}2\ ,\ \frac{y_1+y_2}2\right)=\left(\frac{-2+3}2\ ,\ \frac{1+(-1)}2\right)=\left(\frac12\ ,\ 0\right)

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Answer:

The formula for calculating the width of the window is

w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}

Step-by-step explanation:

<u><em>The question in English is</em></u>

A rectangular window is l meters wide and h meters high, with a perimeter of 6 meters and an area of 2m². What is the formula for calculating the width of the window?

we know that

The perimeter of the window is equal to

P=2(l+w)

we have

P=6\ m

so

6=2(l+w)

simplify

3=(l+w)

isolate the variable l

l=3-w ----> equation A

The area of the window is equal to

A=lw

we have

A=2\ m^2

so

2=lw ----> equation B

substitute equation A in equation B

2=(3-w)w

solve for w

2=3w-w^2

w^2-3w+2=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

w^2-3w+2=0

so

a=1\\b=-3\\c=2

substitute in the formula

w=\frac{-(-3)(+/-)\sqrt{-3^{2}-4(1)(2)}} {2(1)}  --->  formula for calculating the width of the window

w=\frac{3(+/-)\sqrt{1}} {2}

w=\frac{3(+/-)1} {2}

w=\frac{3(+)1} {2}=2\ m

w=\frac{3(-)1} {2}=1\ m

7 0
4 years ago
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