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likoan [24]
2 years ago
14

A cottage has a gable roof. To the nearest foot, how wide is the cottage?A. 12 ftB. 24 ftC. 35 ftD. 70 ft

Mathematics
1 answer:
Sergio [31]2 years ago
7 0

Answer: the answer is B: 24ft

Step-by-step explanation: To find how wide the triangle is identify your angles. You have a right angle which is equal to 90° and an angle that measures 46°. Add up both of these angles and you'll get 136°. A triangle can only have three angles that add up to 180. So subtract 180 and 136 you get 44. Multiply the hypotenuse by sin(46) to get the length of the side facing the opposite way of the angle that measures 44°. You will get 11.8 which is about 12. The other triangle is a congruent triangle meaning that it's angles and sides are the same. Add both 12's up and you have 24ft as your width for the cottage.

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The area of triangle is 48 cm sq,its base is 12 cm. find its altitude​
Mariana [72]

Answer:

its altitude is 8 cm

Step-by-step explanation:

1/2× base ×altitude =48

1/2×12× al =48

6×al =48

al = 8

5 0
3 years ago
33 1/3% of 75<br><br>plz help​
Paraphin [41]

The answer is 25

x 33 1/3% = 75

75 / 33 1/3

0.3333

(75)(0.333) =  25

24.9999999 rounds to 25

Hope this helps, have a BLESSED day! :-)

6 0
3 years ago
Does anybody know how to do this??
boyakko [2]

just divide 200 until u get 25 i think but idk the second one

3 0
3 years ago
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
If f(x) = 2x ^ 2 + 5 squreroot(x - 2) complete the following statement
lubasha [3.4K]

Answer:

hello :

Step-by-step explanation:

f(x) = 2x²+5√(x-2)

f(x) exist : x - 2 ≥ 0  :  x ≥ 2

The domain for f(x) is all real numbers "greater" than   or equal to 2

7 0
3 years ago
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