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likoan [24]
3 years ago
14

A cottage has a gable roof. To the nearest foot, how wide is the cottage?A. 12 ftB. 24 ftC. 35 ftD. 70 ft

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer: the answer is B: 24ft

Step-by-step explanation: To find how wide the triangle is identify your angles. You have a right angle which is equal to 90° and an angle that measures 46°. Add up both of these angles and you'll get 136°. A triangle can only have three angles that add up to 180. So subtract 180 and 136 you get 44. Multiply the hypotenuse by sin(46) to get the length of the side facing the opposite way of the angle that measures 44°. You will get 11.8 which is about 12. The other triangle is a congruent triangle meaning that it's angles and sides are the same. Add both 12's up and you have 24ft as your width for the cottage.

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Simplify<br><br>Square root of 50 over 2 times -4 + square root of 121
kobusy [5.1K]

Answer:

  -9

Step-by-step explanation:

  \sqrt{\dfrac{50}{2}}\cdot(-4)+\sqrt{121}=-4\sqrt{25}+11=-4\cdot5+11\\\\=-20+11=\boxed{-9}

Your calculator can help with this.

4 0
2 years ago
What is the x intercept of y + 4 =− 4(x − 1)
vivado [14]

Answer:

0

Step-by-step explanation:

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3 years ago
What is the length of EF in the right triangle below?
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8 0
3 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

A=152

7 0
3 years ago
The answer and how to solve the problem
SVETLANKA909090 [29]
A
I hope you get it right, you have a god day!!!

7 0
3 years ago
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