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likoan [24]
2 years ago
14

A cottage has a gable roof. To the nearest foot, how wide is the cottage?A. 12 ftB. 24 ftC. 35 ftD. 70 ft

Mathematics
1 answer:
Sergio [31]2 years ago
7 0

Answer: the answer is B: 24ft

Step-by-step explanation: To find how wide the triangle is identify your angles. You have a right angle which is equal to 90° and an angle that measures 46°. Add up both of these angles and you'll get 136°. A triangle can only have three angles that add up to 180. So subtract 180 and 136 you get 44. Multiply the hypotenuse by sin(46) to get the length of the side facing the opposite way of the angle that measures 44°. You will get 11.8 which is about 12. The other triangle is a congruent triangle meaning that it's angles and sides are the same. Add both 12's up and you have 24ft as your width for the cottage.

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Answer:

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5 0
2 years ago
Read 2 more answers
Find the ratio a:b, if 2a−b/6 = b/3
Tom [10]

Answer:

a:b = 2

Step-by-step explanation:

Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).

We have:

2a−b/6 = b/3

Lets sum b/6 in both sides:

2a−b/6 + b/6 = b/3 + b/6

2a = b/3 + b/6

Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:

2a = b/3*(2/2) + b/6

2a = 2b/6 + b/6

2a = 3b/6

2a = b/2, as 3/6 = 1/2

Now lets divide both sides by b to make an a/b appear:

2a/b = (b/2)/b

2a/b = 1/2

Finally, multiply both sides by (1/2) or divide by 2:

(2a/b)/2 = 2

a/b = 2

This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.

7 0
3 years ago
Joaquin writes the following list of numbers.
swat32

From the given list of numbers, the numbers that are:

rational are 26, -3/2, 0, and 9.

irrational are 5.737737773..., and √45.

Any number that can be written in the form of p/q, where p and q are integers, and q ≠ 0, are called rational numbers.

All terminating and non-terminating recurring decimals are rational numbers.

All the numbers that cannot be represented in the rational form of p/q are irrational numbers.

All non-terminating non-recurring decimals are irrational.

All square roots of imperfect square numbers, that is, surds, are irrational numbers.

In the question, we are asked to classify the given list of numbers into rational and irrational numbers.

  • 5.737737773...: It is an irrational number, since its a non-terminating non-recurring decimal.
  • 26: It is rational as it can be represented in the p/q form (26/1).
  • √45: It is irrational as it is a square root of an imperfect square number, that is, it is a surd.
  • -3/2: It is rational as it is in the form p/q.
  • 0: It is rational as it can be represented in the p/q form (0/1).
  • 9: It is rational as it can be represented in the p/q form (9/1).

Thus, from the given list of numbers, the numbers that are:

rational are 26, -3/2, 0, and 9.

irrational are 5.737737773..., and √45.

Learn more about rational and irrational numbers at

brainly.com/question/14994517

#SPJ9

The provided question is incorrect. The correct question is:

Joaquin writes the following list of numbers.

5.737737773..., 26, √45, -3/2, 0, 9.

Which numbers are rational?

Which numbers are irrational?

6 0
1 year ago
For what integer value of x is 3x+5&gt;11 and x-3 &lt;1?
Andre45 [30]
3x + 5 > 11
3x + (5 - 5) > 11 - 5 
3x > 6
3x / 3 > 6 / 3
x > 2

x - 3 < 1
x (-3 + 3) < 1 + 3
x < 4

When subtracting / adding values to both sides, the inequality does not change.

When multiplying / dividing by a positive value, the inequality also doesn't change, but when multiplying , dividing with a negative value, the inequality must be flipped.
7 0
3 years ago
Show that the equation x^3 + x -3 =0 has a solution between 1 and 2. That is the only information given
valentina_108 [34]

Answer:

Step-by-step explanation:

Given that:

f(x) = x^3 + x - 3 = 0

Since the given function is equal to zero, then the function :

f(x) = x^3 + x - 3

where;

x = 1 and

x = 2

f(x) = (1)^3 + (1) - 3 \\  \\ f(x) = 1 + 1 - 3 \\ \\f(x) = -1 < 0

f(2) =  x^3 + x - 3 \\ \\f(2) = (2)^3 + 3 - 3  \\ \\f(2) = 8 + 3 - 3  \\ \\f(2) = 11 - 3 \\ \\f(2) = 8 > 0 \\ \\

Thus; f(1) < 0 and f(2) > 0

8 0
2 years ago
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