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Crazy boy [7]
3 years ago
10

A line includes the points (6, 9) and (3, 3). What is its equation in slope-intercept form?

Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

y=2x-3

Step-by-step explanation:

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Solve the following system of equations. Enter the x-coordinate of the solution. Round your answer to the nearest tenth.
Bezzdna [24]

Answer:

x = 5.7 and y = 3.8

Step-by-step explanation:

We have given a system of equation.

5x+2y = 21                                    eq(1)

-2x+6y = -34                                 eq(2)

We have to find the solution of the given system.

Multiplying eq(1) by 3 , we have

15x+6y = 63

Subtracting above equation from eq(2), we have

15x+6y - (-2x+6y) = 63-(-34)

15x+6y+2x-6y = 63+34

17x+0 = 97

17x = 97

x = 97/17

x = 5.706≅5.7

Putting the value of x in eq(1) , we have

5(5.706)+2y = 21

2y = 21-28.53

2y = 7.53

y = 7.53/2

y = 3.765

We have to round it to the nearest tenth

y = 3.8

Hence, the solution of given system is x = 5.7 and y = 3.8

6 0
3 years ago
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Slav-nsk [51]
I think I did this test and I think it’s A
8 0
3 years ago
The circumference of a circle is a 12.1mm. Find the length of the radius. Give your answer rounded to 1 DP.​
faltersainse [42]

Answer:

1.9

Step-by-step explanation:

r=C/2π

r-12.1/2π=1.9257...

5 0
2 years ago
Read 2 more answers
Find a vector equation and parametric equations for the line segment that joins P to Q. P(1, −1, 4), Q(4, 2, 1)
lesya [120]

Answer:

Step-by-step explanation:

Given points P(1, -1, 4), Q (4,2,1) vector equation of a line joining  the points with position vectors r₀ and r₁ is:

r = (1 - t)r₀ + tr₁

where

t ∈ [0, 1]

and r₀ = P = (1, -1, 4)

r₁ = Q = (4, 2, 1)

r(t) = (1 - t) \langle 1,-1,4\rangle  + t\langle 4,2,1 \rangle

r(t) = \langle 1 - t , -1 + t, 4 - 4t \rangle + \langle 4t, 2t, t \rangle

r(t) = \langle 1 - t+4t , -1 + t+ 2t, 4 - 4t+ t \rangle

r(t) = \langle 1 +3t , -1 +3t, 4 - 3t \rangle

∴

The vector equation r(t) = \langle 1 +3t , -1 +3t, 4 - 3t \rangle where t ∈ [0,1] is:

r(t) = (1+3t)i - (1+3t)j + (4 - 3t)k

The parametric equation is:

x(t) = 1 + 3t

y(t) = -1 + 3t

z(t) = 4 - 3t

(x(t), y(t), z(t) ) = ( 1 + 3t, -1 + 3t, 4 - 3t )

4 0
3 years ago
Read 2 more answers
HELP NEEDED : Solve this using ELIMINATION:<br><br> 8x + 8y = 240<br> 4x + y = 54<br><br> Please!!!!
Licemer1 [7]

4x + y = 54

8x + 2y = 104

8x + 8y - (8x + 2y) = 240 - 104

6y = 136

y=22 2/3

4x+ 22 2/3 = 54

4x= 31 1/3

x= 7 5/6

4 0
4 years ago
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