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3 years ago

5

The cost of two mopeds is the same as the cost of seven bicycles. The cost of one bicycle is $152. Therefore, the cost of one mo

ped is

1 answer:

mafiozo [28]3 years ago

5 0

1 bike = 152

7 bikes = 152*7 = 1064

1 moped = 1064/2 = $532

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MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE

lukranit [14]

Using the normal distribution, it is found that the percentages are given as follows:

3.59% of the grades will be A.

9.98% of the grades will be B.

74.92% of the grades will be C.

8.64% of the grades will be D.

2.87% of the grades will be F.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The prorportion of students who receive an A is <u>one subtracted by the p-value of Z = 1.8</u>.

Looking at the z-table, Z = 1.8 has a p-value of 0.9641.

1 - 0.9641 = 0.0359.

3.59% of the grades will be A.

For B, it is the <u>p-value of Z = 1.8 subtracted by the p-value of Z = 1.1</u>, hence:

0.9641 - 0.8643 = 0.0998.

9.98% of the grades will be B.

For C, it is the <u>p-value of Z = 1.1 subtracted by the p-value of Z = -1.2</u>, hence:

0.8643 - 0.1151 = 0.7492.

74.92% of the grades will be C.

For D, it is the <u>p-value of Z = -1.2 subtracted by the p-value of Z = -1.9</u>, hence:

0.1151 - 0.0287 = 0.0864.

8.64% of the grades will be D.

For F, it is the <u>p-value of Z = -1.9</u>, hence 2.87% of the grades will be F.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

7 0

1 year ago

Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3

maria [59]

Answer:

(x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

(2/x +1/y) -2(1/x -5/y) = (3) -2(7)

11/y = -11 . . . . simplify

y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

2/x +1/-1 = 3

2/x = 4 . . . . . . . add 1

x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

6 0

2 years ago

14389+4309 what is it

kow [346]

The answer is 18,698 :)

8 0

3 years ago

Read 2 more answers

Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon

motikmotik

Given parameters;

Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

Simon has more money than Kande

S > K

if Simon gave Kande K20, they would have the same amount;

if Simon gives $20, his money will be S - 20 lesser;

When Kande receives $20, his money will increase to K + 20

S - 20 = K + 20 ------ (i)

While if Kande gave Simon $22, Simon would then have twice as much as Kande;

if Kande gave Simon $22, his money will be K - 22

Simon's money, S + 22;

S + 22 = 2(K - 22) ------ (ii)

Now we have set up two equations, let us solve;

S - 20 = K + 20 ---- i

S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii

So, S - 20 = K + 20

S + 22 = 2K - 44

subtract both equations;

-20 - 22 = (k -2k) + 64

-42 = -k + 64

k = 106

Using equation i, let us find S;

S - 20 = K + 20

S - 20 = 106 + 20

S = 106 + 20 + 20 = 146

Therefore, Kande has $106 and Simon has $146

3 0

3 years ago

Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If women's weights are

Mariulka [41]

Answer:

$P(141.8$

And we can find this probability with this difference and using the normal standard table:

$P(-0.639$

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(173.6,49.8)$

Where $\mu=173.6$ and $\sigma=49.8$

We are interested on this probability

$P(141.8$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(141.8$

And we can find this probability with this difference and using the normal standard table:

$P(-0.639$

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0

3 years ago