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Mashcka [7]
2 years ago
9

Need help ASAP! Directions and problem in picture;) What is the value of ?

Mathematics
1 answer:
pickupchik [31]2 years ago
8 0

Answer:

105⁰

Step-by-step explanation:

Please refer to the attachment.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

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Graph the functions and approximate an x-value in which the exponential function exceeds the polynomial function. y = 4x y = 7x2
nordsb [41]

Answer:

The Exponential function is

y=4^x

And the polynomial function is

y=7 x^2 +4 x -2

And, we have to find the value of x for which, exponential function exceeds the polynomial function which can be written as

4^x> 7 x^2 +4 x -2

1. When , x= -1

LHS

4^{-1}=\frac{1}{4}=0.25

RHS

=7*(-1)^2 +4 *(-1)-2\\\\=7-4-2=1

2. When , x=0

L HS

 4^0=1

RHS

7*0+4*0-2= -2

3. When ,x= 0.5

L HS

 4^{0.5}=2

RHS

=7*0.25 +4*0.5 -2\\\\= 1.75+2-2\\\\=1.75

4. When , x=2

LHS

 4^{2}=16

RHS

=7*4^2+4*4-2\\\\=112+16-2\\\\=126

The Minimum value for which  exponential function exceeds the polynomial function is , x= 0.5

But,there is other value for which  exponential function exceeds the polynomial function is , x=2.

5 0
2 years ago
Please help will mark brainly
Slav-nsk [51]

the answer is B because

2 2/3 = 8/3

8/3 x 3 = 24/3

24/3 = 8

I hope this helps

4 0
3 years ago
Read 2 more answers
Which quotient will be neither positive nor negative?
vaieri [72.5K]

Answer:

D. It would be D.

Step-by-step explanation:

Because anything divided by zero is zero, and I suppose zero is neither negative nor positive. or vise versa

5 0
3 years ago
Read 2 more answers
Which absolute value expression represents the distance between 3 and −5 on a number line?
lora16 [44]

Answer:

B) To represent  the distance between 3 and −5 on a number line,  the correct expression is  I(3) - (-5)I .

Step-by-step explanation:

Here the point A is given as 3 on number line.

Point B is given as -5 on number line.

To find :  IA-BI

The distance between any two point A and B is given as IA-BI.

Now, to find the absolute value:

IA-BI = I  (3) - (-5)I

or, IA-BI = I (3) + 5I  = I8I

= 8 units

or, IA-BI = 8 units

Hence, on the number line, the distance between -5 and 3 is 8 units.

And, to represent  the distance between 3 and −5 on a number line,  the correct expression is  I(3) - (-5)I .

3 0
2 years ago
6.403124247 to 2 Decimal places please
Bingel [31]
6.40 is to two decimal places
4 0
3 years ago
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