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Irina18 [472]
3 years ago
10

What is the statistical decision regarding the differences between the observed and expected frequencies if the critical value o

f chi-square is 9.488 and the computed value is 6.079
Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

Fail to reject.

Step-by-step explanation:

For a goodness of fit test the decision rule is:

If the calculated value of the test statistic is more than the right tailed critical value of chi-square, then the null hypothesis will be rejected.

The hypothesis for a goodness of fit test is:

<em>H</em>₀: There is no differences between the observed and expected frequencies.

<em>Hₐ</em>: There is a significant differences between the observed and expected frequencies.

The computed value of the test statistic is, 6.079.

The critical value of chi-square is 9.488.

Calculated test statistic < Critical value

                            6.079 < 9.488

Thus, the null hypothesis was failed to rejected.

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A radio station had 205 tickets to a concert. They gave away 4 times as many tickets to listeners as to employees. How many tick
Citrus2011 [14]

Answer:

As per the statement: A radio station had 205 tickets to a concert. They gave away 4 times as many tickets to listeners as to employees.

⇒Let number of tickets Employees have x and Number of ticket Listeners  have 4x

It is also, given that a radio station had 205 ticket to a concert.

⇒ \text{Number of ticket Employees have} +\text{Number of ticket Listeners have} = 205

Then, substitute the given values we have;

4x + x = 205

Combine like terms, we have;

5x = 205

Divide both sides by 5 we have;

x = 41

Therefore, number of tickets did they give away to employees have 41 tickets



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