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2 years ago

10

What is the statistical decision regarding the differences between the observed and expected frequencies if the critical value o

f chi-square is 9.488 and the computed value is 6.079

1 answer:

mel-nik [20]2 years ago

6 0

Answer:

Fail to reject.

Step-by-step explanation:

For a goodness of fit test the decision rule is:

If the calculated value of the test statistic is more than the right tailed critical value of chi-square, then the null hypothesis will be rejected.

The hypothesis for a goodness of fit test is:

<em>H</em>₀: There is no differences between the observed and expected frequencies.

<em>Hₐ</em>: There is a significant differences between the observed and expected frequencies.

The computed value of the test statistic is, 6.079.

The critical value of chi-square is 9.488.

Calculated test statistic < Critical value

6.079 < 9.488

Thus, the null hypothesis was failed to rejected.

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a

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b

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Step-by-step explanation:

From the question we are are told that

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=> $E = 3.569$

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