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Irina18 [472]
2 years ago
10

What is the statistical decision regarding the differences between the observed and expected frequencies if the critical value o

f chi-square is 9.488 and the computed value is 6.079
Mathematics
1 answer:
mel-nik [20]2 years ago
6 0

Answer:

Fail to reject.

Step-by-step explanation:

For a goodness of fit test the decision rule is:

If the calculated value of the test statistic is more than the right tailed critical value of chi-square, then the null hypothesis will be rejected.

The hypothesis for a goodness of fit test is:

<em>H</em>₀: There is no differences between the observed and expected frequencies.

<em>Hₐ</em>: There is a significant differences between the observed and expected frequencies.

The computed value of the test statistic is, 6.079.

The critical value of chi-square is 9.488.

Calculated test statistic < Critical value

                            6.079 < 9.488

Thus, the null hypothesis was failed to rejected.

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2 years ago
A scientist need 10 L of a 20% acid solution for an experiment where she had only a 5% solution and a 40% solution to the neares
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