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navik [9.2K]
3 years ago
5

Which of the following is the solution to the compound inequality

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

3x+5\geq-1\ \ \ |-5\\\\3x\geq-6\ \ \ |:3\\\\x\geq-2\\------------------\\-2x-7\geq5\ \ \ |+7\\\\-2x\geq12\ \ \ \ |:(-2) < 0\\\\x\leq-6

Answer:\ A.\ x\geq-2\ or\ x\leq-6

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Answer:

5

Step-by-step explanation:

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3 years ago
Which of the following are true of F(x)?
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True:
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3 years ago
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Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.
GalinKa [24]

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = x

m∠D = 2x-20°.

Now, let m∠A = m∠B = y

So, m∠C = m∠A + 30° = y+30

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50

Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  2x-20=2(50)-20=100-20=80\°

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

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