Remark
You are using the midpoint formula. Instead of finding the midpoint, you are looking for one of the points, so you have to rearrange the formula a little bit.
Givens
Midpoint (4,2)
One endpoint (6,1)
Object
Find the other endpoint.
Formula
m(x,y) = (x1 + x2)/2, (y1 + y2)/2)
Solution
Find the x value
4 = (6 + x2)/2 Multiply both sides by 2
4*2 = 6 + x2 Subtract 6 from both sides.
8 - 6 = x2
x2 = 2
Find the y value
2 = (1 + y2)/2 Multiply by 2
4 = 1 + y2 Subtract 1 from both sides.
4 - 1 = y2
y2 = 3
Conclusion
R(x,y) = (2,3)
Answer:
the answer is B
Step-by-step explanation:
53,61,69
it’s adding 8 every time.
120=x+y and 10=.05x+.10y
120-x=y then subsitute 10=.05x+.10(120-x) distruibte and solve you can do it feel free to go off of my math.
x(nickels) y(dimes)
Given :
<span>Triangle fgh is inscribed in circle o
</span>
oh = 6 = radius of the circle
<span>∵ fh is congruent to og
</span>
<span>∴ fh = og = radius og the circle = 6
</span>
<span>∵ of = radius of the circle = 6
</span>
<span>∴ oh = fh = of = radius of the circle = 6
</span>
∴ Δ foh is Equilateral Triangle
<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle
</span>
∵ total area of the circle = π r² and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85
The answer is:
<span>the area of the sector formed by angle foh
= 18.85</span>
