Please answer I need this to get a good grade. (;
1 answer:
Answer:
94.74 mol NO₂
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
3714 L O₂ at STP
<u>Step 2: Identify Conversions</u>
RxN: 7 mol O₂ = 4 mol NO₂
STP: 22.4 L = 1 mol
<u>Step 3: Stoichiometry</u>
<u /> = 94.7449 mol NO₂
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
94.7449 mol NO₂ ≈ 94.74 mol NO₂
You might be interested in
Let's start off with the balanced chemical equation:
Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.
Since you have the required mass of NaCl, convert this to moles.
Assuming you know how to find the molar mass of NaCl:
Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:
Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:
Hope this helps :)
Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.
Since you have the required mass of NaCl, convert this to moles.
Assuming you know how to find the molar mass of NaCl:
Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:
Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:
Hope this helps :)