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kap26 [50]
3 years ago
9

____is used as anode for prevention of corrosion 1 aluminium 2 magnesium 3 iron

Chemistry
1 answer:
choli [55]3 years ago
7 0

Answer:

I'm not sure but I think the answer is Cathodic protection.

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Electrical energy can produce many other types of energy.
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A.sound energy
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3 years ago
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Scientists changed the genes of a tomato plant in order to produce a protein which is a natural pesticide. Why would this be cla
soldi70 [24.7K]

Answer:

The plant would be insect-resistant and improve its chances of success.

Explanation:

5 0
3 years ago
How many electrons are represented by a dash (-) in a lewis dot structure compound?
vivado [14]
A. 2
The dash represents two electrons
6 0
3 years ago
In a sealed gas-liquid system at constant temperature, eventually...?
SOVA2 [1]
<h2>Let us study about it .</h2>

Explanation:

Evaporation

It is the process of converting liquid into vapors .

Condensation

It is the process of converting  vapors back into liquid state .

  1. Suppose if we have a sealed container and we are supplying it with no or little heat , we will see that as we increase heat , the particles starts moving faster .
  2. When they move they also colloide and transfer energies .
  3. The kinetic energies of certain molecule increase to an extent that they leave the other particles and escape in atmosphere .
  4. That is evaporation occurs .At the same time when these vapors collide with each other or with the walls of container they get cooled and again get converted to liquid state .

It is seen that  a equilibrium is reached when "rate of evaporation becomes equal to rate of condensation ".

4 0
3 years ago
A 7.50-g sample of iron is heated in oxygen to form an iron oxide. if 10.71 g of the oxide is formed, what is its empirical form
Zielflug [23.3K]
Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
m(iron oxide) = 10,71 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
3 0
3 years ago
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