How do you prove a scalene triangle is a right triangle?
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Answer:
The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%
Explanation:
Here we have
Propane gas with molecular formula C₃H₈, molar mass = 44.1 g/mol combining with O₂ as follows
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Therefore, 1 mole of C₃H₈ combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O
Mass of propane = 0.1240 kg = 124.0 g
Number of moles of propane = mass of propane/(molar mass of propane)
The number of moles of propane = 124/44.1 = 2.812 moles
The molar mass of CO₂ = 44.01 g/mol
Mass of CO₂ = 0.3110 kg = 311.0 g
Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)
The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles
Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂
Therefore;
The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess
Hence
The percentage yield = 83.77%.
Answer:
Mass of HCN produced = 6.75 g
Explanation:
Reaction is as follows:
First calculate the no. of moles of each chemical species.
molecular mass of is 17 g/mol
No. of mol of = 11.5/17 = 0.676 mol
Molecular mass of = 32 g/mol
No. of mol of = 12/32 = 0.375
Molecular mass of = 16 g/mol
No. of mol of = 10.5/16 = 0.656 mol
from the balanced chemical reaction, it is clear that 2-moles ammonia reacts with 3 moles oxygen and 2 moles methane to form 2 moles of HCN.
or, 1-mol ammonia reacts with 1.5 mol oxygen and 1 mol methane to form 1 mol of HCN.
Thus, no. of oxygen present is less than required and so it will act as limiting reagent.
From the chemical equation,
3 moles oxygen produces 2 moles HCN
or one mole oxygen produces (2/3) moles HCN
0.375 moles oxygen produces (2/3) × 0.375 HCN = 0.25 moles of HCN
molar mass of HCN = 27 g/mole
Mass = mol × molar mass
mass of HCN = 27 × 0.25 = 6.75 g