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faust18 [17]
2 years ago
9

The average atomic mass for germanium is 72.631 amu. If germanium occurred as a mixture of the two isotopes below, what would be

the percent abundance of 73Ge in the mixture?
mass of 70Ge = 69.924 amu

mass of 73Ge = 72.923 amu

Percent abundance of 73Ge in nature = ________ %
Chemistry
2 answers:
Leto [7]2 years ago
8 0

Answer:

dora needs help

Explanation:

dsp732 years ago
5 0

Answer:

...........................

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Which statement best describes a typical difference that could be found between the "Analysis" and "Conclusion" sections of a
IgorC [24]

The statement “Only the “Conclusion” section discusses whether the original hypothesis was supported, and both sections suggest further  research”, best describes the difference between analysis and conclusion.

Answer: Option 4

<u>Explanation: </u>

In research, we do experiments and derive the results. Then, those results were analyzed by us. In this analysis part, we compare our results with the related results published elsewhere. Also, we correlate the similarities and point out the differences between our analysis and other reported results.

In conclusion part, we have to check hypothesis or it supported. And, we summarise our analysis and figure out the further research need to be done on that to improvise our research. So, the final statement is the correct option which best describes the difference between analysis and conclusion.

3 0
3 years ago
Help please I am so lost my teacher is no help
uranmaximum [27]

Answer:

B - CALCIUM

Explanation:

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6 0
3 years ago
A balloon contains 0.140 molmol of gas and has a volume of 2.78 LL . If an additional 0.152 molmol of gas is added to the balloo
levacccp [35]

Answer:

The final volume will be 5.80 L

Explanation:

Step 1: Data given

Number of moles gas = 0.140 moles

Volume of gas = 2.78 L

Number of moles added = 0.152 moles

Step 2: Calculate the final volume

V1/n1 = V2/n2

⇒ with V1 = the initial volume = 2.78 L

⇒ with n1 = the initial number of moles = 0.140 moles

⇒ with  V2 = The new volume = TO BE DETERMINED

⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles

2.78/0.140 = V2 /0.292

V2 = 5.80 L

The final volume will be 5.80 L

8 0
3 years ago
A student burns 1.50 mol C3H8 according to the following reaction:
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1.50 mol C3H8 X (3 mol CO2 / 1 mol C3H8) X (44.0 g CO2 / 1 mol CO2) = 198 g CO2

3 0
2 years ago
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in an experiment magnesium ribbon was heated in air the product formed was found heavier than original ribbon.potassium manganat
AlladinOne [14]

Answer:

1: due to difference in reactivity and melting point

2 during the reaction both combine with oxygen in this case magnesium remain solid but some potassium vaporise

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