5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
231
Step-by-step explanation:
because the whole circle has an area of 360 so on the right side there is half and a little more so you would cut it in half so you have 180 and on the right side you still have a little left so thats about 10 so now you have 190 then you add 21 +20 you have 41 +190 =231 hope this helps
The answer to your question would be B.
I hope this helped:D
I think The last one in right
y |2| 6 |10 |14
x |6 |18 |30 |42
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