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3 years ago

Defined by distinct lines which intersect at right angles and at exactly one point.

Mathematics

1 answer:

Fantom [35]3 years ago

3 0

Is the correct answer welcome

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Measureing midpoints

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What midpoints are you wanting to measure?

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3 years ago

Which machine would you use to pry a heavy rock from the ground

Sergio [31]

A lever is a simple machine that helps move or pry a rock from the ground.

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2 years ago

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Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

3 years ago

A parallelogram is shown below: Part A: What is the area of the parallelogram? Show your work. (5 points) Part B: How can you de

aksik [14]

Part A) The area of a parallelogram is base × height.

3 × 2/3 = 6/3 = 2

2 feet squared is the area of the whole parallelogram.

Part B) The diagonal of a parallelogram separates it into two congruent triangles.

The area of each triangle will be:

base × height × 1/2

3 × 2/3 × 1/2 = 6/6 = 1

1 foot squared is the area for each triangle.

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3 years ago

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Solve 2x2 + 3x – 7 = x2 + 5x + 39 for x.

Brrunno [24]

The answer to this question is:
x = 1 + or - the square root of 47

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3 years ago