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3 years ago

What number would go in the boxes to have the sum of 4?

Mathematics

1 answer:

rosijanka [135]3 years ago

6 0

Answer:

2.964 is the answer.

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The product of twice a number and six is the same as the difference of eleven times the number and 5/6. Find the number.

laila [671]

Answer:

9.16666

Step-by-step explanation:

now answer my question or ask a freind

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4 years ago

Abby has been absent from class. How would you explain to her what absolute value is?

lara [203]

Answer:

absolute value is the number itself regardless if it is negative or positive

7 0

3 years ago

A factor tree for 61 that is not nothing

ddd [48]

False because the factor tree for 61 is 1 and 61

5 0

3 years ago

Solve this -5-x=-3x-17

drek231 [11]

Answer:

-6

Step-by-step explanation:

5 0

3 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

3 years ago