Answer:
7.28 moles Ag°
Explanation:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Given 7.28 moles 7.28 moles
To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...
Limiting reactant determination:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Cu: 7.28 / 1 = 7.28
AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃
Solving Problem depends on AgNO₃; Cu will be in excess.
Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.
In his Gold Foil experiment, few particles were deflected strongly, where as he thought all particles will go straight through the foil (some did though, which are called electrons.) J. J. Thompson, Rutherford's former teacher, proposed that if there are negative charge particles (he named them electrons), there must also be a positive charge particles; Rutherford proved his theory right, and he called the positive charge protons. He also found that inside the atom, there must be a positive charge that is clustered in a tiny region in its center, which is called the nucleus.
A spring tide occurs when there is a new or full moon in the solar system.
<h3>What is Spring tide?</h3>
This is the type of tide which occurs when the sun, moon and earth are in line and occurs between three to four times per year.
Lunar and solar tides also line up and reinforce each other to produce this type of tide.
Read more about Spring tide here brainly.com/question/11545040
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